[英]How would i generate a new random number
import random
guess = '0'
while (guess) != 'exit':
answer = random.randrange(1,100)
answer = str(answer)
guess = input('Enter a number between 1 and 100 or enter exit to exit: ')
if not guess.isdigit():
if guess == "exit":
print('Game closed')
break
else:
print('Your guess was not a digit, try again')
guess = (guess)
if guess == answer:
print('Correct')
elif guess > answer :
print('Too high, try again')
elif guess < answer :
print('Too low, try again')
在您猜对了正确答案后,我将如何生成一个新的随机数?
这里的主要问题是,即使您猜错了,您实际上每次都会生成一个新的数字。 相反,您应该在循环之外生成第一个随机数,并且仅在猜测正确的情况下才生成新的随机数:
import random
guess = '0'
answer = random.randrange(1, 100)
while (guess) != 'exit':
answer = str(answer)
guess = input('Enter a number between 1 and 100 or enter exit to exit: ')
if not guess.isdigit():
if guess == "exit":
print('Game closed')
break
else:
print('Your guess was not a digit, try again')
guess = (guess)
if guess == answer:
print('Correct')
answer = random.randrange(1, 100) #make new random number if guess is correct
elif guess > answer :
print('Too high, try again')
elif guess < answer :
print('Too low, try again')
我不确定我是否正确理解您的评论。 您可以使用random.randint(a,b)来获取整数,而不是十进制数。
( https://docs.python.org/3/library/random.html#random.randint )
import random
guess = '0'
answer = random.randint(1, 100)
while (guess) != 'exit':
answer = str(answer)
guess = input('Enter a number between 1 and 100 or enter exit to exit: ')
if not guess.isdigit():
if guess == "exit":
print('Game closed')
break
else:
print('Your guess was not a digit, try again')
guess = (guess)
if guess == answer:
print('Correct')
answer = random.randint(1, 100) #make new random number if guess is correct
elif guess > answer :
print('Too high, try again')
elif guess < answer :
print('Too low, try again')
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