如何在熊貓中打印特定列的內容

Question

我有2列的excel文件（第1列=單詞，第2列=線索）。 我想做的是使用熊貓，隨機選擇一個工作表“單詞”列，打印它的線索（來自列2）並創建一個a子手游戲。 如果沒有打印線索部分，下面的代碼就可以正常工作，但是我無法完成的是為隨機選擇的單詞打印相應的線索。 任何想法如何做到這一點？

import random
import pandas as ps
df1=ps.read_excel("C:/Python27/hangman_clues.xlsx")
#Randomly select a word from the 'Word' Column and convert to lowercase
word=random.choice(df1["Word"]).lower()
print "Welcome to Hangman"
print "Your Clue is"
#This is where I want to print the clue from 2nd column based on the 
randomly selected word which I am unable to accomplish. Tried 
df2=df1.set_index("Word",drop=False) but did not help much.

#below code works fine
guessedword=list('_'*len(word))
ctr=0
while ctr<len(word)+5:
    guessedchar=raw_input("Guess a char:")
    if guessedchar in word:
           getindex=[i.start() for i in re.finditer(guessedchar,word)]
           for index in getindex:
              guessedword[index]=guessedchar
              getindex=[]
              guessword="".join(guessedword)
           print str(guessedword)
           if word==guessword:
               print "you win"
               break


    ctr=ctr+1

Answer 1

您可以獲取一個隨機索引，並將其用於單詞和相應線索。

index = random.randint(0, len(df1["Word"]))
word = df1["Word"][index]
print("Your clue is {}".format(df1["Clue"][index]))

Answer 2

您可以使用df1.sample(n=1) ，它將返回一個隨機選擇的行的DataFrame。

df_random_obs = df1.sample(n=1)
word = df_random_obs['Word']
clue = df_random_obs['Clue']