遍歷有序字典python的多個值（針對同一鍵）

Question

我有一個有序的字典，其中同一鍵有多個值。 我需要遍歷所有項目，並對每個值執行不同的操作。

該字典如下：

OrderedDict([('1', ['file a','file1','file2','file3', 'Substringb']), ('2', ['file c', 'Substringd']), ('3', ['filed', 'Substringe']),('4', ['file f', 'Substringg']), ('5', ['file h', 'Substringi'])]

每個項目都有文件路徑和一個子字符串。 我無法控制從其他功能接收多少文件。 我想打開它們中的每一個並尋找子字符串。 現在，當我執行以下操作時，我得到的值太多，無法解壓縮：

下面是我使用的代碼：當我提取值並嘗試遍歷each_file時，它不起作用-打印每個文件只會打印文件路徑的第一個字符[ex：'C'，而文件路徑為“'C： \\ Users \\ xxxxxx \\ Documents \\ something.txt“]。 請幫助我解決這個問題。 TIA。

for each_key, (each_file, each_substr) in d.iteritems():  #Giving too many values to unpack error since there are multiple files coming in[no control on how many to expect] 
    for each in each_file:
       print each
       with open(each_file) as f: ## This is giving error as the each is not working as I would expect it to.

Answer 1

您只需要1個循環即可提取所有數據。 只需使用iteritems()並解壓值元組即可獲取所需的字符串

for each_key, (each_file, each_substr) in d.iteritems():
    print each_key, each_file, each_substr

Answer 2

我知道了。

for each_key, each_value in d.iteritems():   
each_substring = each_value[1] #Since my substring is appended at the end and am removing it from the each_values list in the below step after saving it here
each_file = each_value[:-1] #Grabbing all files except the last one
for each in each_file:
   print each
   with open(each_file) as f: ## Now this works!!! 

“對於d.iteritems（）中的each_key，（每個文件，each_substr）：”如果我們不知道要期待多少個項目，則效率不是很高[看起來就是這樣]