查找元素的值是唯一的，並且列表中的所有元素都相同

Question

查找元素的值是唯一的，並且列表中的所有元素都相同。

  >>> a = ['1','1']
  >>> all(x == a[0] for x in a)
  True
  >>> a = ['1','2']
  >>> all(x == a[0] for x in a)
  False
  >>> a = ['1-2-3','1-2-3']
  >>> all(x == a[0] for x in a)
  True

  #### Diffent Example #####################
  >>> a = ['1-2-2','1-2-2']
  >>> all(x == a[0] for x in a)
  True
  Expected Output False.

  any elements must contain unique values, but here it is repeated that is 2-2.

始終列出格式：

   a = ["1", "2", "3","4"]
   b = ["1-2-3", "1-2-2"] # That is dash separated 

Answer 1

您可以嘗試使用附加條件拆分-並檢查長度是否與set相匹配（與list比較），即添加(len(x.split('-')) == len(set(x.split('-'))) ：

>>> a = ['1-2-2','1-2-2']
>>> all((x == a[0]) and (len(x.split('-')) == len(set(x.split('-')))) for x in a)

結果：

False

對於其他示例：

>>> a = ['1-2-3','1-2-3']
>>> all((x == a[0]) and (len(x.split('-')) == len(set(x.split('-')))) for x in a)

結果：

True