從拆分器面板中刪除后無法顯示 winform

Question

我有 2 個表格（Form1 和 Form2）。 Form1 有一個帶有兩個面板的分離器。 我在拆分器控件的 panel2 中添加了 Form2。 我想在不創建 Form2 的新實例的情況下彈出和彈出 Form2。 請在下面找到代碼片段：

public partial class Form1 : Form
{
 private Form2 form2 = null;
 public Form1()
 {
     InitializeComponent();
 }
 private void Form1_Load(object sender, EventArgs e)
 {
        form2 = new Form2();
        form2.FormBorderStyle = System.Windows.Forms.FormBorderStyle.None;
        form2.Dock = DockStyle.Fill;
        form2.TopLevel = false;
        splitContainer1.Panel2.Controls.Add(form2);
        form2.Pop += new EventHandler(PopForm);
        form2.Show();
 }
 //button click event handler from Form2
 private void PopForm(object sender, EventArgs e)
 {
     Button b = sender as Button;
     if(b.Text.ToUpper() == "POPOUT")
     {
         splitContainer1.Panel2Collapsed = true;
         splitContainer1.Panel2.Controls.Remove(form2);
         //need to show the form without creating a new instance to maintain state
         form2 = new Form2();
         form2.SelectedMailId = 1;
         form2.Pop += new EventHandler(PopForm);
         form2.SetButtonText = "PopIn";
         form2.Show();                
     }
     else
     {
         //this works fine
         splitContainer1.Panel2Collapsed = false;
         form2.FormBorderStyle = System.Windows.Forms.FormBorderStyle.None;
         form2.Dock = DockStyle.Fill;
         form2.TopLevel = false;
         splitContainer1.Panel2.Controls.Add(form2);
     }
   }
 }

彈出時如何在不創建新實例的情況下顯示 Form2？

Answer 1

雖然彈出設置表單邊框樣式和頂級

 if(b.Text.ToUpper() == "POPOUT")
 {
     splitContainer1.Panel2Collapsed = true;
     splitContainer1.Panel2.Controls.Remove(form2);
     //need to show the form without creating a new instance to maintain state
     form2.TopLevel = true;
     form2.FormBorderStyle = FormBorderStyle.Sizable;
     // setup your settings
     form2.Show();                
 }