I have 2 forms (Form1 and Form2). Form1 has a splitter with two panels. I have added Form2 in the panel2 of the splitter control. I want to pop in and pop out Form2 without creating a new instance of Form2. Please find the code snippet below:
public partial class Form1 : Form
{
private Form2 form2 = null;
public Form1()
{
InitializeComponent();
}
private void Form1_Load(object sender, EventArgs e)
{
form2 = new Form2();
form2.FormBorderStyle = System.Windows.Forms.FormBorderStyle.None;
form2.Dock = DockStyle.Fill;
form2.TopLevel = false;
splitContainer1.Panel2.Controls.Add(form2);
form2.Pop += new EventHandler(PopForm);
form2.Show();
}
//button click event handler from Form2
private void PopForm(object sender, EventArgs e)
{
Button b = sender as Button;
if(b.Text.ToUpper() == "POPOUT")
{
splitContainer1.Panel2Collapsed = true;
splitContainer1.Panel2.Controls.Remove(form2);
//need to show the form without creating a new instance to maintain state
form2 = new Form2();
form2.SelectedMailId = 1;
form2.Pop += new EventHandler(PopForm);
form2.SetButtonText = "PopIn";
form2.Show();
}
else
{
//this works fine
splitContainer1.Panel2Collapsed = false;
form2.FormBorderStyle = System.Windows.Forms.FormBorderStyle.None;
form2.Dock = DockStyle.Fill;
form2.TopLevel = false;
splitContainer1.Panel2.Controls.Add(form2);
}
}
}
How can I show the Form2 without creating a new instance when popping out?
While popout setup the form border styled and toplevel
if(b.Text.ToUpper() == "POPOUT")
{
splitContainer1.Panel2Collapsed = true;
splitContainer1.Panel2.Controls.Remove(form2);
//need to show the form without creating a new instance to maintain state
form2.TopLevel = true;
form2.FormBorderStyle = FormBorderStyle.Sizable;
// setup your settings
form2.Show();
}
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