如何將項目從列表末尾移到開始？

Question

using System.Collections;
using System.Collections.Generic;
using UnityEngine;

public class MoveObjects : MonoBehaviour
{
    public float speed = 3f;

    private GameObject[] objectstoMove;
    private List<GameObject> objectsMoving = new List<GameObject>();
    private float distanceTravelled = 0;
    private Vector3 lastPosition;

    // Use this for initialization
    public void Init()
    {
        objectstoMove = GameObject.FindGameObjectsWithTag("Test");
        objectsMoving = new List<GameObject>(objectstoMove);
        lastPosition = objectstoMove[objectstoMove.Length].transform.position;
    }

    // Update is called once per frame
    void Update()
    {
        if (objectstoMove != null)
        {
            float step = speed * Time.deltaTime;
            for (int i = 0; i < objectstoMove.Length; i++)
            {
                if(distanceTravelled >= 50.0f)
                {
                    objectsMoving.Remove(objectsMoving[objectsMoving.Count]);
                }

                objectsMoving[i].transform.Translate((objectsMoving[i].transform.up + objectsMoving[i].transform.forward) * step);

                distanceTravelled += Vector3.Distance(objectsMoving[objectsMoving.Count].transform.position, lastPosition);
                lastPosition = objectsMoving[objectsMoving.Count].transform.position;
            }
        }
    }
}

在這一部分中，我要獲取列表中的最后一個對象並將其移動到列表的開頭：

if(distanceTravelled >= 50.0f)
                    {
                        objectsMoving.Remove(objectsMoving[objectsMoving.Count]);
                    }

通常的想法是將最后一個項目對象從列表移動到列表的開頭，並一直保持移動對象，但是每次列表中的最后一個對象距離distanceTravelled> = 50.0f時，都將其移動到列表的開頭。名單。 如果我沒記錯的話，與循環相同。

Answer 1

做這樣的事情：

if(distanceTravelled >= 50.0f)
{
    var moveToFirst = objectsMoving.Last();
    objectsMoving.RemoveAt(objectsMoving.Count-1);
    objectsMoving.Insert(0, moveToFirst);
}