將帶有列表的字典轉換為csv文件，其中列為鍵，值在行中

Question

嗨，我有一本字典，其中包含包含它的指示符，如下所示：

{'url' : [ 'malware.com ', 'hack.net ', 'paypalz.org' ] 'IP' ['104.223.89.166' , 104.223.89.136] 'emailIdentifier' : ['liler@bikurcholim.net']}

我需要將其轉換為csv，其中鍵是列，值是行。 我試圖在這種情況下的stackoverflow流中找到解決方案，但我沒有找到解決方案。 任何糖尿怎么辦？

謝謝

with open('\\cybernet\\cyber_indicators.csv', 'w') as csv_file:

    writer = csv.writer(csv_file)

    dict_writer = csv.DictWriter(csv_file, keys)

    for key, value in dictionary.items():

        writer.writerow([key, value])

Answer 1

import csv
dictionary={'url' : [ 'malware.com ', 'hack.net ', 'paypalz.org' ] ,'IP' : ['104.223.89.166' , '104.223.89.136'] ,'emailIdentifier' : ['liler@bikurcholim.net']}
list_temp=[]
with open('data.csv','w') as csv_file:
    writer = csv.writer(csv_file)
    writer.writerow(dictionary.keys())
    for key, value in dictionary.items():
        list_temp.append(value)
    list_last=[x for x in dictionary.values()]
    max_length=0
    for item in list_last:
        if(len(item)>max_length):
            max_length=len(item)
    for item in list_last:
        append_count=max_length-len(item)
        for i in range(append_count):
            item.append('')
    zipped_list=list_last=set(zip(*list_temp))
    for item in zipped_list:
        writer.writerow(item)

data.csv

url,IP,emailIdentifier
malware.com ,104.223.89.166,liler@bikurcholim.net
paypalz.org,,
hack.net ,104.223.89.136,