[英]how can i make this code shorter using for loop
我想知道如何使用for循環使這段代碼更短,有什么建議嗎? 我很抱歉問你們一個簡單的問題
謝謝
if (int(classes[0][0])==1):
print('icis_0.8_water')
if (int(classes[0][0])==2):
print('nevia')
if (int(classes[0][0])==3):
print('Xiaomi')
if (int(classes[0][0])==4):
print('hyundai_mouse')
if (int(classes[0][0])==5):
print('peace_stapler')
if (int(classes[0][1])==1):
print('icis_0.8_water')
if (int(classes[0][1])==2):
print('nevia')
if (int(classes[0][1])==3):
print('Xiaomi')
if (int(classes[0][1])==4):
print('hyundai_mouse')
if (int(classes[0][1])==5):
print('peace_stapler')
if (int(classes[0][2])==1):
print('icis_0.8_water')
if (int(classes[0][2])==2):
print('nevia')
if (int(classes[0][2])==3):
print('Xiaomi')
if (int(classes[0][2])==4):
print('hyundai_mouse')
if (int(classes[0][2])==5):
print('peace_stapler')
你可以用字典
d = {
1: 'icis_0.8_water',
2: 'nevia',
3: 'Xiaomi',
4: 'hyundai_mouse',
5: 'peace_stapler'
}
print(d[int(classes[0][0])])
print(d[int(classes[0][1])])
print(d[int(classes[0][2])])
希望能幫助到你..
你可以試試:
results = ['icis_0.8_water', 'nevia', 'Xiaomi', 'hyundai_mouse', 'peace_stapler']
for i in range(3):
for j in range(1, 6):
if(int(classes[0][i]) == j):
print(results[j - 1])
當然,如果您要檢查更多的“類”元素,或者您想獲得更多可能的結果,則必須更改范圍(並添加其他外部“ for”循環以遍歷classes [k] [i]元素,其中“ k”為改變)。
for i in range(len(classes[0])):
if (int(classes[0][i])==1):
print('icis_0.8_water')
if (int(classes[0][i])==2):
print('nevia')
if (int(classes[0][i])==3):
print('Xiaomi')
if (int(classes[0][i])==4):
print('hyundai_mouse')
if (int(classes[0][i])==5):
print('peace_stapler')
如果要循環分類行數組,請在外部添加for循環。
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