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[英]How do I select pandas row if a column in that row contains a substring present in a list
[英]How do I set the column and row indexes on a multidimensional list in pandas
我有一組要從Google工作表中檢索的數據。 它以以下格式返回:
[['Incident Severity', '# of Incidents by Severity'], ['Sev 1', '0'], ['Sev 2', '0'], ['Sev 3', '3'], ['Sev 4', '2']]
我已使用from_records將其導入到Pandas中,使用df.head()給了我以下內容:
0 1
0 Incident Severity # of Incidents by Severity
1 Sev 1 0
2 Sev 2 0
3 Sev 3 3
4 Sev 4 2
但是,第一行需要設置為標題,第一列應該為索引。 我設法通過執行以下操作來更改列標題:
df.columns = df.iloc[0]
df = df.reindex(df.index.drop(0))
這給了我:
0 Incident Severity # of Incidents by Severity
1 Sev 1 0
2 Sev 2 0
3 Sev 3 3
4 Sev 4 2
如何刪除第一個索引列,以便得到下表:
Incident Severity # of Incidents by Severity
Sev 1 0
Sev 2 0
Sev 3 3
Sev 4 2
我對熊貓和數據框還很陌生,所以如果我遺漏了一些明顯的東西,請原諒我。 我試圖用谷歌搜索它,但沒有找到我需要知道的!
使用列表的索引創建DataFrame
:
L = [['Incident Severity', '# of Incidents by Severity'],
['Sev 1', '0'],
['Sev 2', '0'],
['Sev 3', '3'],
['Sev 4', '2']]
df = pd.DataFrame(L[1:], columns=L[0])
print (df)
Incident Severity # of Incidents by Severity
0 Sev 1 0
1 Sev 2 0
2 Sev 3 3
3 Sev 4 2
無法刪除索引,一種解決方案(確實很糟糕)是將索引轉換為空值:
df.index = [''] * len(df)
print (df)
Incident Severity # of Incidents by Severity
Sev 1 0
Sev 2 0
Sev 3 3
Sev 4 2
但是,如果需要將沒有索引的DataFrame寫入文件,請向to_csv
添加參數index=False
:
print (df.to_csv(index=False))
Incident Severity,# of Incidents by Severity
Sev 1,0
Sev 2,0
Sev 3,3
Sev 4,2
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