[英]Cube Root using iterations and bisection
我試圖通過將數字二等分然后縮小范圍來找到它的立方根。 我以這種方式有平方根的程序,但是立方根方法只是繼續循環而從未給出答案。 我不確定我哪里出錯了,需要一些建議。
public class myFunc
{
public static double squareRoot(double value, double precision)
{
double low, high, middle;
high = 1;
low = value;
middle = (high + low) / 2;
Console.WriteLine("{0,20:n12}{1,20:n12}{2,20:n12}", low, middle, high);
while ((high-low)>precision)
{
if ((middle * middle) <value)
{
low = middle;
}
else
{
high = middle;
}
middle = (high + low) / 2;
Console.WriteLine("{0,20:n12}{1,20:n12}{2,20:n12}", low, middle, high);
}
return (middle);
}
public static double cubeRoot(double value, double precision)
{
double low, high, middle;
high = value;
low = 1;
middle = (high + low) / 3;
Console.WriteLine("{0,20:n12} {1,20:n12} {2,20:n12}", low, middle, high);
while ((high - low) > precision)
{
if ((middle * middle*middle)>value)
{
high = middle;
}
else
{
low = middle;
}
middle = (high + low) / 3;
Console.WriteLine("{0,20:n12} {1,20:n12} {2,20:n12}", low, middle, high);
}
return (middle);
}
middle = (high + low) / 3;
假設高是10,低是8,中是... 6? 這不是您想要的范圍嗎?
中間值仍應為(high + low) / 2
,此搜索第三個根的原因只是(middle * middle*middle)>value
測試。
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