[英]Filter an array with multiple conditions
數組看起來像
products = [
{
"id": "5c94aa7b7a37631ce2a97a72",
"material": "5c9485d37804946bc487ce59",
},
{
"id": "5c94aa7b7a37631ce2a97a72",
"material": "5c94862a7804946bc487ce5e",
},
{
"id": "5c94aa7b7a37631ce2a97a72",
"material": "5c9486397804946bc487ce61",
},
{
"id": "5c94a0a87a37631ce2a979de",
"material": "5c9485d37804946bc487ce59",
},
{
"id": "5c94a0a87a37631ce2a979de",
"material": "5c94862a7804946bc487ce5e",
},
{
"id": "5c94a0a87a37631ce2a979de",
"material": "5c9486397804946bc487ce61",
}
]
而當我嘗試僅刪除id="5c94aa7b7a37631ce2a97a72"
和material="5c9485d37804946bc487ce59"
我使用過濾功能
filtered = products.filter(x => x.id !== id && x.material !== material);
它將刪除所有具有這些ID和材料的產品。 在此功能中設置條件的正確方法是什么?
只需使用||
而不是&&
,因此兩個條件都必須為false,以便filter
回調返回false
:
const products = [{ "id": "5c94aa7b7a37631ce2a97a72", "material": "5c9485d37804946bc487ce59", }, { "id": "5c94aa7b7a37631ce2a97a72", "material": "5c94862a7804946bc487ce5e", }, { "id": "5c94aa7b7a37631ce2a97a72", "material": "5c9486397804946bc487ce61", }, { "id": "5c94a0a87a37631ce2a979de", "material": "5c9485d37804946bc487ce59", }, { "id": "5c94a0a87a37631ce2a979de", "material": "5c94862a7804946bc487ce5e", }, { "id": "5c94a0a87a37631ce2a979de", "material": "5c9486397804946bc487ce61", } ]; console.log(products.length); const id = "5c94aa7b7a37631ce2a97a72"; const material = "5c9485d37804946bc487ce59"; const filtered = products.filter(x => x.id !== id || x.material !== material); console.log(filtered.length); console.log(filtered);
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