[英]Python return filepath/filename of most recent csv file stored in directory
[英]Extract only most recent file based on filename
我想從已更新的文件中解壓縮最新文件。 這是我的代碼:
def main():
dest_dir = 'C:/Users/PycharmProjects/kpi/flats'
zip_file = 'Z:/OUT.zip'
with ZipFile(zip_file) as zipObj:
for zip_info in zipObj.infolist():
if zip_info.filename[-1] == '/':
continue
if zip_info.filename.startswith('homeware/R2D2/DATA/OUT/Flat/FlatFile_r2d2_01012018'):
print(zip_info.filename)
zip_info.filename = os.path.basename(zip_info.filename)
zipObj.extract(zip_info,dest_dir)
提取的文件是:
homeware/R2D2/DATA/OUT/Flat/Flat_01012018_180216.csv
homeware/R2D2/DATA/OUT/Flat/Flat_01012018_210147.csv
homeware/R2D2/DATA/OUT/Flat/Flat_01012018_230148.csv
但我只希望最后一個基於文件名而不是元數據
所以我所做的不是在每次迭代時提取,而是將滿足'if'要求的文件附加到列表中。 然后我提取了該列表的最大值,這是我正在尋找的文件。 這是更新的代碼:
def main():
dest_dir = 'C:/Users/mbelahce040119/PycharmProjects/kpi/flats'
zip_file = 'Z:/DATA/OUT/COMMON_2018/201810/OUT_201810.zip'
with ZipFile(zip_file) as zipObj:
files_sat = list()
for zip_info in zipObj.infolist():
if zip_info.filename[-1] == '/':
continue
if zip_info.filename.startswith('homeware/R2D2/DATA/OUT/Flat/FlatFile_r2d2_01012018'):
print(zip_info.filename)
files_sat.append(zip_info.filename)
zip_info.filename = os.path.basename(max(files))
zipObj.extract(max(files_sat), dest_dir)
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