如何使用Python跟蹤用戶的猜測？ 嘗試次數=嘗試次數+ 1不起作用

Question

我需要跟蹤用戶在簡單的猜測游戲中輸入的猜測數量。

我嘗試使用trys = 0，然后將trys設置為= trys + 1。即使執行此操作，即使用戶猜測的嘗試次數超過一次，代碼也會打印“您已經嘗試了1次”。

碼：

attempts = 0;
print("Hello, welcome to the game. You will be choosing a number 
between 1 and 100. You can only guess up to 10 times.")

for tries in range(tries_allowed):
    print("You only get 10 tries.")
    break 

while attempts < 10:
    guess = int(input("Please guess a number"));
    attempts_used= attempts + 1;
    if guess > random_number:
            print("Guess is too high, try a smaller number");
    elif guess < random_number:
            print("Guess is too low, try a higher number");
    elif guess == random_number:
            attempts_used=str(attempts_used)
            print("Correct- you win in", attempts_used, "guesses");
            exit();
else:
    if tries_allowed == 10:
       print("You failed to guess in time")

my_list= [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
my_list.append(attempts_used)
print(my_list)

Answer 1

您永遠不會更新attempts變量，您已經創建了一個名為attempts_used的新變量，您不需要這樣做。

只在attempts使用的地方使用attempts_used

注意：在執行此操作時，您應該擺脫while循環中所謂的“魔術數字”或硬編碼限制

while attempts < tries_allowed:

Answer 2

稍微整理一下代碼，顯示+=計數方法可用於您的腳本。 就像其他人所說的那樣，原始代碼正在創建一個全新的變量attempts_used ，它只是attempts + 1 ，而attempts仍然為0。

也可能是attempts = attempts + 1 ， +=表示同一件事。

為了使int一個str的Python為打印目的，它並不需要被存儲到一個獨立的變量，只需調用str()圍繞它，除非你打算單獨使用的字符串。

import random

random_number = random.randint(1,100)

attempts = 0
tries_allowed = 10
print("Hello, welcome to the game. You will be choosing a number between 1 and 100")

print("You only get " + str(tries_allowed) + " tries.")

my_list = []

while attempts < tries_allowed:
    guess = int(input("Please guess a number: "))
    if guess in my_list:
        print("You have already guessed " + str(guess))
        continue
    attempts += 1
    my_list.append(guess)
    if guess > random_number:
            print("Guess is too high, try a smaller number")
    elif guess < random_number:
            print("Guess is too low, try a higher number")
    elif guess == random_number:
            print("Correct- you win in", str(attempts), "guesses")
            break
else:
    if attempts == 10:
       print("You failed to guess in time")

for item in my_list:
    print(item)

Answer 3

您的“ attemps”變量保持為0，因此attemps_used（attempts + 1）始終為1。您必須將兩個變量合並為一個變量才能對其進行控制（attempts = attempts + 1）

Answer 4

該代碼還將檢查先前的輸入並顯示一條消息。

import random
# Hello World program in Python

attempts = 0
print("Hello, welcome to the game. You will be choosing a number between 1 and 100. You can only guess up to 10 times.")

random_number = random.randint(1, 101)
#print(random_number)
my_list= []

for tries in range(10):
    print("You only get 10 tries.")
    guess = int(input("Please guess a number: "))
    if guess in my_list:
        print("You already guessed this number!!")
    my_list.append(guess)
    attempts += 1

    if guess > random_number:
        print("Guess is too high, try a smaller number")
    elif guess < random_number:
        print("Guess is too low, try a higher number")
    else:
        print("Correct- you win in", tries + 1, "guesses")
        attempts = -1
        break


if attempts is 10 and attempts is not -1:   
    print("You failed to guess in time")
print("Attempts : ", my_list)