簡體   English   中英

合並並組合兩列不同的數據幀

[英]Merge and combine 2 columns of different dataframe

我有2個數據幀:

ID             word
1              srv1
2              srv2
3              srv1
4              nan
5              srv3
6              srv1
7              srv5
8              nan
ID             word
1              nan
2              srv12
3              srv10
4              srv8
5              srv4
6              srv7
7              nan
8              srv9

我需要的是在ID上合並2個數據幀並組合列字來得到:

ID             word
1              srv1 
2              srv2 , srv12
3              srv1 , srv10
4              srv8
5              srv3 , srv4
6              srv1 , srv7
7              srv5
8              srv9

使用以下代碼

merge = pandas.merge(df1,df2,on="ID",how="left")
merge["word"] = merge[word_x] + " , " + merge["word_y"]

我正進入(狀態:

ID             word
1              nan 
2              srv2 , srv12
3              srv1 , srv10
4              nan
5              srv3 , srv4
6              srv1 , srv7
7              nan
8              nan

這不是正確的解決方案。

您可以使用Series.str.catna_rep選項填充word列,即使其中一個源列位於nan ,然后使用str.strip來修剪任何前導/尾隨' , '而不是單詞之間。

m['word'] = m['word_x'].str.cat(m['word_y'], sep=' , ', na_rep='').str.strip(' , ')

回報

   ID word_x word_y          word
0   1   srv1    NaN          srv1
1   2   srv2  srv12  srv2 , srv12
2   3   srv1  srv10  srv1 , srv10
3   4    NaN   srv8          srv8
4   5   srv3   srv4   srv3 , srv4
5   6   srv1   srv7   srv1 , srv7
6   7   srv5    NaN          srv5
7   8    NaN   srv9          srv9

您可以使用np.select選擇現有值或連接值。

試試這個:

import pandas as pd
import numpy as np
from io import StringIO

df1 = pd.read_csv(StringIO("""
ID             word
1              srv1
2              srv2
3              srv1
4              nan
5              srv3
6              srv1
7              srv5
8              nan"""), sep=r"\s+")

df2 = pd.read_csv(StringIO("""
ID             word
1              nan
2              srv12
3              srv10
4              srv8
5              srv4
6              srv7
7              nan
8              srv9"""), sep=r"\s+")


conditions = [(~df1["word"].isna()) & df2["word"].isna(), df1["word"].isna() & (~df2["word"].isna()), (~df1["word"].isna()) & (~df2["word"].isna())]
choices = [df1["word"], df2["word"], df1["word"] + "," + df2["word"]]

df1["word"] = np.select(conditions,choices)

print(df1)

輸出:

   ID        word
0   1        srv1
1   2  srv2,srv12
2   3  srv1,srv10
3   4        srv8
4   5   srv3,srv4
5   6   srv1,srv7
6   7        srv5
7   8        srv9

根據我的想法,我首先要擺脫那些nan的:

df_1.fillna(value="")
df_2.fillna(value="")

然后我會再次嘗試合並,看看你是否得到了你想要的東西。

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM