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[英]How do i write a regular expression for the following pattern in python?
[英]How to write the following pattern
我正在嘗試在 python 中打印以下模式,但沒有得到所需的輸出:
0
2 2
4 4 4
6 6 6 6
我已經使用了以下代碼,但沒有得到所需的輸出
n = int (input("Enter number : "))
for i in range (n):
print (i *2 )
嘗試這個:
n = int (input("Enter number : "))
for i in range (n):
print (' '.join([str(i * 2) for _ in range(i + 1)]) )
您需要打印數字i+1
次。
for i in range (n):
for _ in range(i+1):
print (i * 2," ", end='') # print without newlines
print() # end the line
以下簡單的代碼可能會有所幫助:
n = int (input("Enter number : "))
j = 1
k = 0
for i in range(n):
s = str(k)+' '
print(s*j)
j += 1
k += 2
如果n = 4
,那么它將打印以下內容:
0
2 2
4 4 4
6 6 6 6
n = int (input("Enter number : "))
count = 1
for i in range (n):
res = str(i*2) + " "
print (res * (i+1))
print n
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