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[英]Assigning multiple column values in a single row of pandas DataFrame, in one line
[英]Pandas dataframe, how to set multiple column values in a single row?
例如:
import pandas as pd
df_1 = pd.DataFrame({"A":[1, 5, 3, 4, 2],
"B":[3, 2, 4, 3, 4],
"C":[2, 2, 7, 3, 4],
"D":[4, 3, 6, 12, 7]})
df_2 = pd.DataFrame(index = list(range(5)),columns = ['a','c'])
df_2.loc[2,['a','c']] = df_1.loc[2,['A','C']]
print(df_1.loc[2,['A','C']])
print(df_2)
我有:
A 3
C 7
Name: 2, dtype: int64
a c
0 NaN NaN
1 NaN NaN
2 NaN NaN
3 NaN NaN
4 NaN NaN
顯然我未能在一行中同時設置多個單元格。 有什么辦法可以做到這一點? (使用循環除外)
Here working index alignment, so because different a
, c
with A
, C
columns it set missing values (here not change), solution is set by numpy array for avoid it:
df_2.loc[2,['a','c']] = df_1.loc[2,['A','C']].values
print (df_2)
a c
0 NaN NaN
1 NaN NaN
2 3 7
3 NaN NaN
4 NaN NaN
如果替換匹配的列名,它工作得很好:
df_2.loc[2,['a','c']] = df_1.loc[2,['A','C']].rename({'A':'a','C':'c'})
#alternative
#df_2.loc[2,['a','c']] = df_1.rename(columns={'A':'a','C':'c'}).loc[2,['a','c']]
print (df_2)
a c
0 NaN NaN
1 NaN NaN
2 3 7
3 NaN NaN
4 NaN NaN
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