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如何在序列中找到最長的相鄰 integer 值

[英]How to find the longest length adjacent integer values in a sequence

對於這個問題,我想在一個序列中獲得最長的相鄰整數。 我覺得我接近答案,但不知道如何解決它。 誰能幫幫我?

輸入: [1, 2, 5, 5, 5, 6, 6, 6, 8, 8]

預期 Output: 12(555)66688

我的 output: 12(555)6(66)8

我的代碼:

L = [1, 2, 5, 5, 5, 6, 6, 6, 8, 8]
print(L)
inRun = False
last = None
max_value = 0
count = 0
for i in range(len(L) - 1):
    if inRun:
        if L[i] != L[i - 1]:
            if count > max_value:
                max_value = count
                last = i
            print(')', end='')
            inRun = False
            count = 0
        else:
            count += 1
    else:
        if L[i] == L[i + 1]:
            count += 1
            print('(', end='')
            inRun = True
    print(L[i], end='')
if inRun:
    print(')'

編輯

使用 collections 的簡化代碼。 此外,我添加了序列中元素的第一個和最后一個索引。

from collections import Counter

L = [1, 2, 5, 5, 5, 6, 6, 6, 8, 8, 8]
print(L)

cnt = Counter(L)
value, max_value = cnt.most_common(1)[0]

firstIndex = L.index(value)

before_seq = ''.join(str(n) for n in L[:firstIndex])
seq = ''.join(str(n) for n in L[firstIndex : firstIndex + max_value])
after_seq = ''.join(str(n) for n in L[firstIndex + max_value:])

print("{}({}){}".format(before_seq, seq, after_seq))

print("first index: {}\nlast index: {}".format(firstIndex, firstIndex + max_value - 1))

上一個答案

我為您准備了兩個解決方案,因為我不知道您所說的“最長運行”到底是什么意思,而且我也不知道您的代碼中哪里有問題。 在第一個代碼中,您有一個 output: 12(555)(666)88。 在第二個你有:12(555)66688。 我希望我有所幫助:)

第一: Output 12(555)66688

L = [1, 2, 5, 5, 5, 6, 6, 6, 8, 8]
print(L)

max_value = 0
count = 1

for i in range(len(L)):
    for j in range(i + 1, len(L)):
        if L[i] == L[j]:
            count = count + 1
        else:
            if max_value < count:
                max_value = count

            count = 1
            break

    if max_value < count:
        max_value = count
        count = 1

index = 0
count = 1

for i in range(len(L)):
    for j in range(index + 1, len(L)):
        if L[index] == L[j]:
            count = count + 1
        else:
            break

    if count == max_value:
        print('(', end='')
        for k in range(index, index + max_value):
            print(L[k], end='')
        print(')', end='')
        index = index + max_value
        count = 1
        max_value = max_value + 1
    else:
        for k in range(index, index + count):
            print(L[k], end='')
        index = index + count
        count = 1

    if index >= len(L):
        break

第二Output 12(555)(666)88

L = [1, 2, 5, 5, 5, 6, 6, 6, 8, 8]
print(L)

max_value = 0
count = 1

for i in range(len(L)):
    for j in range(i + 1, len(L)):
        if L[i] == L[j]:
            count = count + 1
        else:
            if max_value < count:
                max_value = count

            count = 1
            break

    if max_value < count:
        max_value = count
        count = 1

index = 0
count = 1

for i in range(len(L)):
    for j in range(index + 1, len(L)):
        if L[index] == L[j]:
            count = count + 1
        else:
            break

    if count == max_value:
        print('(', end='')
        for k in range(index, index + max_value):
            print(L[k], end='')
        print(')', end='')
        index = index + max_value
        count = 1
    else:
        for k in range(index, index + count):
            print(L[k], end='')
        index = index + count
        count = 1

    if index >= len(L):
        break

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