如何在csv python中交換行和刪除列

Question

這是我的 csv 輸入

,,A01.0 Брюшной тиф
0,"Тиф брюшной, Паратиф, Тиф, Паратифозная лихорадка",

我在我的代碼之后得到的輸出。

0,

這是我想要的，我有 11000 個像這樣的 csv 文件

"Тиф брюшной, Паратиф, Тиф, Паратифозная лихорадка",A01.0 Брюшной тиф

import csv

data = []
with open('/Users/gfidarov/Desktop/Python/CSV/synonims copy/syn8.csv') as inf:
    reader = csv.reader(inf)
    for row in reader:
        data.append(row)

with open('/Users/gfidarov/Desktop/Python/CSV/merged/syn.csv', 'w') as outf:
    writer = csv.writer(outf)
    writer.writerow([data[1][0], data[0][1]])

Answer 1

import csv


cols_to_remove = [0]# Column indexes to be removed (starts at 0)

cols_to_remove = sorted(cols_to_remove, reverse=True)# Reverse so we remove from the end first
row_count = 0# Current amount of rows processed

input_file = ('/Users/gfidarov/Desktop/Python/CSV/synonims copy/syn13.csv')
output_file = ('/Users/gfidarov/Desktop/Python/CSV/merged/syn.csv')
with open(input_file, "r") as source:
    reader = csv.reader(source)
    with open(output_file, "w", newline='') as result:
        writer = csv.writer(result)
        for row in reader:
            row_count += 1
            print('\r{0}'.format(row_count), end='') # Print rows processed
            for col_index in cols_to_remove:
                del row[col_index]
            writer.writerow(row)

使用此代碼，我只能刪除一個 csv，但我無法弄清楚如何對整個文件夾執行此操作

Answer 2

問題Concat 2 行數據並寫入選定的列

import csv, io

CSV = """,,A01.0 Data1
0,"Sentence 1",
,,A02.0 Data2
0,"Sentence 2",
,,A03.0 Data3
0,"Sentence 3",
"""

data = []
with io.StringIO(CSV) as inf:
    data = [record for record in csv.reader(inf)]

# concat every ziped pair of 2 lists into one list
data2 = [r[0] + r[1] for r in zip(data[0::2], data[1::2])]

with io.StringIO() as out_fh:
    writer = csv.writer(out_fh)
    for rec in data2:
        # Write only Column 4 and 2
        writer.writerow((rec[4], rec[2]))

    print(out_fh.getvalue())

輸出：

 Sentence 1,A01.0 Data1 Sentence 2,A02.0 Data2 Sentence 3,A03.0 Data3