如何在csv python中交换行和删除列

Question

这是我的 csv 输入

,,A01.0 Брюшной тиф
0,"Тиф брюшной, Паратиф, Тиф, Паратифозная лихорадка",

我在我的代码之后得到的输出。

0,

这是我想要的，我有 11000 个像这样的 csv 文件

"Тиф брюшной, Паратиф, Тиф, Паратифозная лихорадка",A01.0 Брюшной тиф

import csv

data = []
with open('/Users/gfidarov/Desktop/Python/CSV/synonims copy/syn8.csv') as inf:
    reader = csv.reader(inf)
    for row in reader:
        data.append(row)

with open('/Users/gfidarov/Desktop/Python/CSV/merged/syn.csv', 'w') as outf:
    writer = csv.writer(outf)
    writer.writerow([data[1][0], data[0][1]])

Answer 1

import csv


cols_to_remove = [0]# Column indexes to be removed (starts at 0)

cols_to_remove = sorted(cols_to_remove, reverse=True)# Reverse so we remove from the end first
row_count = 0# Current amount of rows processed

input_file = ('/Users/gfidarov/Desktop/Python/CSV/synonims copy/syn13.csv')
output_file = ('/Users/gfidarov/Desktop/Python/CSV/merged/syn.csv')
with open(input_file, "r") as source:
    reader = csv.reader(source)
    with open(output_file, "w", newline='') as result:
        writer = csv.writer(result)
        for row in reader:
            row_count += 1
            print('\r{0}'.format(row_count), end='') # Print rows processed
            for col_index in cols_to_remove:
                del row[col_index]
            writer.writerow(row)

使用此代码，我只能删除一个 csv，但我无法弄清楚如何对整个文件夹执行此操作

Answer 2

问题Concat 2 行数据并写入选定的列

import csv, io

CSV = """,,A01.0 Data1
0,"Sentence 1",
,,A02.0 Data2
0,"Sentence 2",
,,A03.0 Data3
0,"Sentence 3",
"""

data = []
with io.StringIO(CSV) as inf:
    data = [record for record in csv.reader(inf)]

# concat every ziped pair of 2 lists into one list
data2 = [r[0] + r[1] for r in zip(data[0::2], data[1::2])]

with io.StringIO() as out_fh:
    writer = csv.writer(out_fh)
    for rec in data2:
        # Write only Column 4 and 2
        writer.writerow((rec[4], rec[2]))

    print(out_fh.getvalue())

输出：

 Sentence 1,A01.0 Data1 Sentence 2,A02.0 Data2 Sentence 3,A03.0 Data3