[英]`TypeError: strptime() argument 0 must be str, not <class 'bytes'>`
[英]TypeError: strptime() argument 1 must be str, not Period
我有這個數據框。
import pandas as pd
from datetime import datetime
df = pd.DataFrame({'id': [11,22,33,44,55],
'name': ['A','B','C','D','E'],
'timestamp': [1407617838,965150022,1158531592,1500701864,965149631]})
df
id name timestamp
0 11 A 2014
1 22 B 2000
2 33 C 2006
3 44 D 2017
4 55 E 2000
df['timestamp'] = pd.to_datetime(df['timestamp'], unit='s')
df['timestamp'] = df['timestamp'].dt.to_period('Y')
y1 = df['timestamp'].iloc[0]
y2 = df['timestamp'].iloc[1]
d1 = datetime.strptime(y1, "%Y")
d2 = datetime.strptime(y2, "%Y")
diff = abs((d2 - d1).days)
print(diff)
我已將時間戳轉換為實際日期並獲取年份。 我想要兩個時間戳的前兩行之間的差異。 例如 (abs (2014-2000) = 4)
如果您通過timeseries的dt
訪問器獲取年份,則會得到整數(而不是“Period”對象):
df['timestamp'] = pd.to_datetime(df['timestamp'], unit='s')
df['timestamp'] = df['timestamp'].dt.year
y1 = df['timestamp'].iloc[0]
y2 = df['timestamp'].iloc[1]
# d1 = datetime.strptime(y1, "%Y") <- No need to recast to datetime!
# d2 = datetime.strptime(y2, "%Y")
diff = abs((y2 - y1))
print(diff)
>>> 14
如您所見,我評論了這兩行是您試圖將年份重新轉換為datetime
對象。 這有什么原因嗎? 根據您的問題,我假設您想要年數的差異。 如果您想要時間戳之間的確切天數,則應該這樣做:(無需轉換和重新轉換):
df['timestamp'] = pd.to_datetime(df['timestamp'], unit='s')
y1 = df['timestamp'].iloc[0]
y2 = df['timestamp'].iloc[1]
diff = abs((y2 - y1).days)
print(diff)
>>> 5122
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.