[英]Looping through to find element by xpath and then click on each element found
[英]Looping through and modify each element of a column
給定這樣的數據集
import pandas as pd
d = {'description': ["abcd","efgh","ijkl"], 'code': ["A","K","Z"]}
df = pd.DataFrame(data=d)
description code
0 abcd A
1 efgh K
2 ijkl Z
我的目標是得到這個
description code
0 "abcd" A
1 "efgh" K
2 "ijkl" Z
這段代碼只是打印出我的目標
for row in df["description"]: #accessing to each row
print(f'"{row}"') #"modifying" each row
這就是產生
"abcd"
"efgh"
"ijkl"
我試圖設置這樣的東西,但它不正確
rows = df.shape[0]
i = 0
while i < rows:
f'"{df.loc[i,"description"]}"'
#wrong
或類似的東西
df1["description"]=df1["description"].apply(lambda ??
你可以簡單地試試這個:
df['description1'] = '"'+ df['description'] + '"'
df
description code description1
0 abcd A "abcd"
1 efgh K "efgh"
2 ijkl Z "ijkl"
通過行迭代,您可以執行以下操作:
for i, row in df.iterrows():
new_val = something
if <condition>:
new_val = something_else
df.at[i,'description'] = new_val
使用你的 while 循環,它看起來像這樣:
rows = df.shape[0]
i = 0
while i < rows:
df.iloc[i,:]['description'] = '"' + df.iloc[i,:]['description'] + '"'
i = i+1
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