c# 中的秒表（統一）

Question

我正在做一扇門（類似於 Doom 64 的門），我有這個代碼：

public class aperturaPorta : MonoBehaviour
{
public Transform playerCheck;
public Vector3 halfSize = new Vector3 (3f, 3f, 0.5f);
public LayerMask playerLayer;
bool playerEntering = false;

public BoxCollider collider;
public MeshRenderer renderer;

bool aprendo = false;
bool chiudendo = false;

public float openSpeed;
int counter = 1;
public int tick = 99;

// Update is called once per frame
void Update()
{
    playerEntering = Physics.CheckBox(playerCheck.position, halfSize, Quaternion.identity, playerLayer, QueryTriggerInteraction.UseGlobal);

    if (playerEntering && Input.GetButtonDown("e")) {
        aprendo = true;
        chiudendo = false;
    } 

    if (counter == 100) {
        chiudendo = true;
    }

    if (aprendo) {
        transform.position += new Vector3 (0f, openSpeed, 0f);
        counter += 1;
        if (counter > tick) {
            aprendo = false;
            chiudendo = true;
        }
    }

    if (chiudendo) {
        transform.position -= new Vector3 (0f, openSpeed, 0f);
        counter -= 1;
        if (counter < 1) {
            chiudendo = false;
        }
    }
}
}

這項工作，但門在完成打開時開始關閉，但它太快了所以我想實現一個兩三秒秒表，這樣當它完成門開始關閉時，我該怎么做？ 謝謝你

ps：對不起，我是團結的新手

Answer 1

如果我理解正確，您想要在門打開之前簡單延遲一下嗎？ 保持相同的代碼結構，您可以為此添加其他計數器。

public float openSpeed;
int counter = 1;
public int tick = 99;
public int delayTicks = 100;
private int delayCounter = 0;

// Update is called once per frame
void Update()
{
    playerEntering = Physics.CheckBox(playerCheck.position, halfSize, Quaternion.identity, playerLayer, QueryTriggerInteraction.UseGlobal);

    if (playerEntering && Input.GetKeyDown(KeyCode.P))
    {
        aprendo = true;
        chiudendo = false;
    }

    if (counter == 100)
    {
        chiudendo = true;
    }

    if (aprendo)
    {
        transform.position += new Vector3(0f, openSpeed, 0f);
        counter += 1;
        if (counter > tick)
        {
            delayCounter = delayTicks;
            aprendo = false;
        }
    }

    if (delayCounter > 0) 
    {
        delayCounter--;
        if (delayCounter <= 0)
        {
            chiudendo = true;
        }
    }
    else if (chiudendo)
    {
        transform.position -= new Vector3(0f, openSpeed, 0f);
        counter -= 1;
        if (counter < 1)
        {
            chiudendo = false;
        }
    }
}