遍歷 object 數組並根據多個條件對其進行過濾

Question

我有 object 數組，其中包含大量重復/無用的數據。 我需要根據客戶 ID 進行過濾，然后選擇最新日期的 object。 數據看起來像這樣：

let data = [
  {
    CUSTOMER_PERMANENT_ID: "2495",
    EMAIL: "abs@gmail.com",
    EVENT_ACTIVATION_TIME: "2019-10-25 13:57:38.79",
  },
  {
    CUSTOMER_PERMANENT_ID: "2495",
    EMAIL: "abs@gmail.com",
    EVENT_ACTIVATION_TIME: "2019-10-28 20:04:49.016",
  },
  {
    CUSTOMER_PERMANENT_ID: "2495",
    EMAIL: "abs@gmail.com",
    EVENT_ACTIVATION_TIME: "2019-10-28 20:04:49.019",
  },
  {
    CUSTOMER_PERMANENT_ID: "5995",
    EMAIL: "John@gmail.com",
    EVENT_ACTIVATION_TIME: "2019-10-28 17:24:10.98",
  }
]

我嘗試了以下 function，但它僅在有兩個重復對象時才有效，如果有兩個以上，則返回所有對象。

public fixDcppSelectedClientData() {
    let result = [];

    for (let item of this.arr) {
      for (let checkingItem of this.arr) {
        if (
          this.arr.indexOf(item) !=
            this.arr.indexOf(checkingItem) &&
          item.CUSTOMER_PERMANENT_ID == checkingItem.CUSTOMER_PERMANENT_ID &&
          new Date(item.EVENT_ACTIVATION_TIME).getTime() <
            new Date(checkingItem.EVENT_ACTIVATION_TIME).getTime()
        ) {
          if (result.indexOf(checkingItem) == -1) {
            result.push(checkingItem);
          }
        }
      }
    }
    console.log("filtered data is ", result);
  }

我需要更多地研究這個話題，但是如果有人能在此期間提供幫助，那就太好了。

問候

Answer 1

let id = "2495"
const query = data
    .filter( obj => obj.CUSTOMER_PERMANENT_ID === id )
    .sort( (obj1, obj2) => 
        (obj1.EVENT_ACTIVATION_TIME < obj2.EVENT_ACTIVATION_TIME) ? 1 : -1 
    )

console.log('latest', query[0]);
console.log('second to latest', query[1]);
console.log('all with this id', query)

Answer 2

此代碼過濾器重復 id

 var newArr = data.filter((x, index, self) => index === self.findIndex((t) => ( t.CUSTOMER_PERMANENT_ID === x.CUSTOMER_PERMANENT_ID))); console.log(newArr);