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如何根據特定單元格值“['0'] not found in axis”刪除 df 中的一行

[英]How do I delete a row in my df based on a specific cell value "['0'] not found in axis"

我有以下 df,我試圖查看第一列中第一行的值是什么,以及它是否等於本例中的預定字符“0”。 我也試過:

if df[col_titles[0]].values[0] == x:
            print(True)
            df  = df.drop(x)

哪個不起作用並且有完全相同的錯誤(在下面發布)。

  First Column Name Second Column Name Third Column Name Fourth Column Name
0                 0                  3                 6                  4
1                 2                  5                 5                  7

df = pd.DataFrame({'First Column Name':  ["0", 2],
        'Second Column Name': ["3", 5],
        'Third Column Name': ["6", 5],
        'Fourth Column Name': ["4", 7],
        })
col_titles = df.columns.values.tolist()
x = df[col_titles[0]].values[0]
print(x)

if df[col_titles[0]].values[0] == "0":
        print(True)
        df  = df.drop(df[col_titles[0]].values[0])

退貨

0
True
Traceback (most recent call last):
  File "test.py", line 42, in <module>
    df  = df.drop(x)
  File "C:\Python38\lib\site-packages\pandas\core\frame.py", line 3990, in drop
    return super().drop(
  File "C:\Python38\lib\site-packages\pandas\core\generic.py", line 3936, in drop
    obj = obj._drop_axis(labels, axis, level=level, errors=errors)
  File "C:\Python38\lib\site-packages\pandas\core\generic.py", line 3970, in _drop_axis
    new_axis = axis.drop(labels, errors=errors)
  File "C:\Python38\lib\site-packages\pandas\core\indexes\base.py", line 5017, in drop
    raise KeyError(f"{labels[mask]} not found in axis")
KeyError: "['0'] not found in axis"

所需 output

  First Column Name Second Column Name Third Column Name Fourth Column Name
1                 2                  5                 5                  7

我們不在這里循環

dfsub = df[df.iloc[:,0]!='0']
Out[13]: 
  First Column Name Second Column Name Third Column Name Fourth Column Name
1                 2                  5                 5                  7

這應該會給你你需要的結果:

df.loc[df['First Column Name'] != '0']

在此處輸入圖像描述

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