我正在制作一個函數，它返回 FizzBu​​zz 列表中所有數字的總和。 我認為這會很好但不起作用。 在 Python 中

Question

結果是 0 如果我輸入 15 而不是，它應該是 60。 我不知道為什么，但 n_numlist 是空的。 我的錯誤在哪里？ 我找不到它了！！ 有人能找到嗎？ 請幫我！！

#This is my code:

def to_fizzbuzz(number):
    if number % 15 == 0:
        return 'FizzBuzz'

    if number % 3 == 0:
        return 'Fizz'

    if number % 5 == 0:
        return 'Buzz'

    else:
        return str(number)
        # return i

def main():
    N = int(input())
    # this list concludes "FizzBuzz", "Fizz" or "Buzz"
    fblist = []
    for number in range(1, 10**6):
        result = to_fizzbuzz(number)
        fblist.append(result)

    # the list up to N
    n_list = fblist[0:N]
    # this list contains only numbers and up to N

    n_numlist = []

    for s in n_list:
        if s.isdigit == True:
            n_numlist.append(s)

    print(sum(n_numlist))


main()

Answer 1

您需要將for s in n_list循環中的for s in n_list更改for s in n_list ：

for s in n_list:
    if s.isdigit() == True:
        n_numlist.append(int(s))

因為isdigit()是一個函數，所以需要在它的末尾加上()才能調用它。

因為您將數字作為字符串return str(number) - return str(number) - 它無法對它們求和，因此當您將它們附加到n_numlist時，您需要將它們轉換回整數。

Answer 2

x = int(input())

inputList = list(range(1,x+1)) #creating a list [1,x]
stringList = [str(a) for a in inputList] #changing int elements to string

for n, i in enumerate(stringList): #n shows which element from list, i shows this element

    if int(i) %15 == 0: #changing to int because we are doing math
        stringList[n] = "FizzBuzz" 

    elif int(i) %5 == 0:
        stringList[n] = "Fizz"

    elif int(i) %3 == 0:
        stringList[n] = "Buzz"

print(stringList) #let's see our new list

last_list = [] #lets add output list

for a in stringList: 
        if a.isdigit() == True: #you forgot put () to isdigit by the way 
            last_list.append(a) 

int_last_list = [int(a) for a in last_list] #we are changing all elements to int because we are going to do some math.

print(sum(int_last_list))