在 C 中打印 uint64_t* 值

Question

我正在使用以下代碼：

    size_t offset = (rand() << 12) % chunk_size;
    uint64_t *addr = (uint64_t*) (chunk+offset);
    fprintf(stdout,"addr: %" PRIx64 " ", addr);

我包含了<inttypes.h>庫，但出現以下錯誤：

error: format ‘%lx’ expects argument of type ‘long unsigned int’, but argument 3 has type ‘uint64_t *’ {aka ‘long unsigned int *’} [-Werror=format=]
fprintf(stdout,"addr: %" PRIx64 " ", addr);  
                                       uint64_t * {aka long unsigned int *}

In file included from filename.c:5:
/usr/include/inttypes.h:121:34: note: format string is defined here
  121 | # define PRIx64  __PRI64_PREFIX "x"
cc1: all warnings being treated as errors
make: *** [Makefile:8: filename.o] Error 1

為什么？

謝謝你。

Answer 1

問題是您要打印的類型是uint64_t *而不是uint64_t ，因此如果要打印指針（ addr ），只需在printf使用%p ，否則您需要使用*取消引用指針。