[英]How could I pass generic interface as a method parameter?
所以我目前正在試驗泛型,我剛剛偶然發現了一個令人震驚的問題。 我真的對它的工作原理有一個抽象的想法,但在尋找答案后,我變得更加困惑。
我首先想使用泛型構造函數創建 2 個新類,而不是使用它們的函數。 一個類應該將第二個類作為參數來使用方法 Attack() 和動態 (class2.health - class1.damage),但它必須實現一個 IDamagable 接口。
我可能會犯一些奇怪的錯誤。 對不起。
public class GenericsIdeas : MonoBehaviour
{
public interface IDamagable<T>
{
void TakeDamage(T dmg);
}
public class Enemy<T1, T2> : IDamagable<T1>
{
T1 damage;
T2 health;
public void Attack(IDamagable d)
{
d.TakeDamage((dynamic)damage);
}
public void TakeDamage(T1 damage)
{
dynamic dmg = (dynamic)damage;
dynamic hp = (dynamic)health;
health -= dmg;
Debug.Log("Enemy health: " + health);
}
public Enemy(T1 t1, T2 t2)
{
damage = t1;
health = t2;
}
}
public class Player<T1, T2> : IDamagable<T1>
{
T1 damage;
T2 health;
public void Attack(IDamagable d)
{
d.TakeDamage((dynamic)damage);
}
public void TakeDamage(T1 damage)
{
dynamic dmg = (dynamic)damage;
dynamic hp = (dynamic)health;
health -= dmg;
Debug.Log("Player health: " + health);
}
public Player(T1 t1, T2 t2)
{
damage = t1;
health = t2;
}
}
void Start()
{
Player<int, int> player = new Player<int, int>(6, 10);
Enemy<float, float> enemy = new Enemy<float, float>(4.32f, 20.61f);
player.Attack(enemy.IDamagable); //???
}
}
我建議這種轉變:
public interface IDamagable
{
void TakeDamage<T>(T dmg);
}
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