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[英]create ID column in dataframe based on other column values / Pandas -Python
[英]Create ID column in a pandas dataframe
我有一個包含交易日志的數據框。 我的問題是我沒有任何 ID 來匹配股票的買賣。 股票可以多次交易,我想有一個 ID 來匹配每筆完成的交易。 我的原始數據幀是一個帶有時間戳的順序時間序列數據幀。 下面的例子說明了我的問題,我需要按順序匹配和 ID 交易的股票。 非常簡單的例子:
df1 = pd.DataFrame({'stock': ['A', 'B', 'C', 'A','C', 'A', 'A'],
'deal': ['buy', 'buy', 'buy', 'sell','sell', 'buy', 'sell']})
df1
Out[84]:
stock deal
0 A buy
1 B buy
2 C buy
3 A sell
4 C sell
5 A buy
6 A sell
這是我想要的輸出:
df1 = pd.DataFrame({'stock': ['A', 'B', 'C', 'A','C', 'A', 'A'],
'deal': ['buy', 'buy', 'buy', 'sell','sell', 'buy', 'sell'],
'ID': [1, 2, 3, 1,3, 4, 4]})
df1
Out[82]:
stock deal ID
0 A buy 1
1 B buy 2
2 C buy 3
3 A sell 1
4 C sell 3
5 A buy 4
6 A sell 4
有任何想法嗎?
嘗試這個:
m = df1['deal'] == 'buy'
df1['ID'] = m.cumsum().where(m)
df1['ID'] = df1.groupby('stock')['ID'].ffill()
df1
輸出:
stock deal ID
0 A buy 1.0
1 B buy 2.0
2 C buy 3.0
3 A sell 1.0
4 C sell 3.0
5 A buy 4.0
6 A sell 4.0
細節:
嘗試這個:
import pandas as pd
df1 = pd.DataFrame({'stock': ['A', 'B', 'C', 'A','C', 'A', 'A'],
'deal': ['buy', 'buy', 'buy', 'sell','sell', 'buy', 'sell']})
def sequential_buy_sell_id_generator(df1):
column_length = len(df1["stock"])
found = [0]*column_length
id = [0]*column_length
counter = 0
for row_pointer_head in range(column_length):
if df1["deal"][row_pointer_head]=="buy":
id[row_pointer_head]= counter
counter+=1
found[row_pointer_head] = 1
id[row_pointer_head]= counter
for row_pointer_tail in range(row_pointer_head+1, column_length):
if df1["stock"][row_pointer_head]== df1["stock"][row_pointer_tail] and df1["deal"][row_pointer_tail] =="sell" and found[row_pointer_tail] == 0:
found[row_pointer_tail] = 1
id[row_pointer_tail]= counter
break
df1 = df1.assign(id = id)
return df1
print(sequential_buy_sell_id_generator(df1))
輸出:
enter code here
stock deal id
0 A buy 1
1 B buy 2
2 C buy 3
3 A sell 1
4 C sell 3
5 A buy 4
6 A sell 4
另一個例子:
For df1 = pd.DataFrame({'stock': ['A', 'B', 'C', 'A','C', 'A', 'A'],
'deal': ['buy', 'buy', 'buy', 'buy','sell', 'sell', 'sell']})
stock deal ID
0 A buy 1
1 B buy 2
2 C buy 3
3 A buy 4
4 C sell 3
5 A sell 1
6 A sell 4
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