試圖創建一個隨機字母循環，但 python 錯誤

Question

    import random

def number_to_letter():
    n = random.randint(1, 26)
    if n == 1:
        n = "A"
        return n
    elif n == 2:
        n = "B"
        return n
    elif n == 3:
        n = "C"
        return n
    else:
        n = "Out of Range."
        return n

def items_in_url(loops):
    url = ""
    i = loops
    while i <= loops:
        url += number_to_letter()
        i += 1
    return url

length_of_url = input("How long would you like the URL? ")
items_in_url(length_of_url)

這是我收到的錯誤：

How long would you like the URL? 3
Traceback (most recent call last):
  File "C:/Users/cmich/PycharmProjects/pythonProject/RandomNumber.py", line 28, in <module>
    items_in_url(length_of_url)
  File "C:/Users/cmich/PycharmProjects/pythonProject/RandomNumber.py", line 24, in items_in_url
    i += 1
TypeError: can only concatenate str (not "int") to str

Process finished with exit code 1

如果我在 function 之外聲明 url，我會得到另一個錯誤。 如果我嘗試 str(url) 我會得到另一個錯誤。 該腳本的基本思想是能夠在提示后輸入一個值，然后將代碼運行該次數，並返回一個最終字符串。 我希望這是有道理的。 我只是在學習 Python 並且在任何地方都找不到答案。

Answer 1

當你得到一個input時，它會作為一個字符串返回。 Python 文檔：

如果存在提示參數，則將其寫入標准 output 而不帶尾隨換行符。 function 然后從輸入中讀取一行，將其轉換為字符串（去除尾隨換行符），然后返回。

使用int() function 將length_of_url轉換為 integer，然后運行 function：

...
length_of_url = int(input("How long would you like the URL? "))
items_in_url(length_of_url)

Answer 2

length_of_url作為字符串輸入，但從未轉換為 int。 您應該將其轉換為 int：

length_of_url = int(input("How long would you like the URL? "))

Answer 3

如果我正確理解了您想要的內容，則您不需要所有代碼。 您所要做的就是以下代碼：

import random
while True:
  LETTERS = ("a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z")
  g = random.choice(LETTERS)
  print(g)