簡體   English   中英

我怎樣才能提高這個跳躍?

[英]How Can I Improve This Jump?

視頻<這是我的問題,我的跳躍跳躍得很快,而且我沒有時間從我跳躍的地方移動毆打有沒有一種方法可以在不減慢精靈 fps 的情況下改善這種跳躍? 如果我試圖減慢我的精靈 fps,這會導致我的精靈在我跳躍時多次播放它的 animation 方式。 我試圖使這個跳躍盡可能平滑,但現在它的跳躍方式很快,而且 animation 的播放速度也很快

我的跳躍在哪里

# our main loop
run = True
while run:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False


    keys = pygame.key.get_pressed()


    if playerman.direction == "right":
        playerman.direction = "Idle"

    if playerman.direction == "left":
        playerman.direction = "leftid"

    


    if keys[pygame.K_SPACE]: #  -------------- IF WE CLICK SPACE THEN WE SHOULD PLAY JUMP ANIMATION
        playerman.direction = "jump"
        


    # player moving
    if not playerman.isJump: # -------------- make our player fall 
        playerman.y += playerman.fall
        playerman.fall += 1
        playerman.isJump = False

        collide = False
        if playerman.rect.bottom >= 605:
            collide = True
            playerman.isJump = False
            playerman.JumpCount = 10
            playerman.y = 605 - playerman.height

        if collide:
            if keys[pygame.K_SPACE]:
                playerman.isJump = True

            playerman.fall = 1

            # -------------- this is the jUmp logic where I am having the problem
    else:
        if playerman.JumpCount >= -10:
            playerman.y -= (playerman.JumpCount*abs(playerman.JumpCount))*0.4
            playerman.JumpCount -= 1
        else:
            playerman.JumpCount = 10
            playerman.isJump = False
   
            if playerman.direction == "jump":         # if we click jump then it should play the jump then go back to the "idle"
                playerman.direction = "Idle"



我的鼠標精靈 class


# our player class
class player:
    def __init__(self,x,y,height,width,color):
        self.x = x
        self.y = y
        self.height = height
        self.width = width
        self.idle = [pygame.image.load("grey_mouse/idle (" + str(i) + ").png") for i in range(1, 21)]
        self.leftid = [pygame.image.load("grey_mouse/id (" + str(i) + ").png") for i in range(1, 21)]

        self.Right = [pygame.image.load("grey_mouse/walk (" + str(i) + ").png") for i in range(1, 9)]
        self.left = [pygame.image.load("grey_mouse/left (" + str(i) + ").png") for i in range(1, 9)]
        self.jump = [pygame.image.load("grey_mouse/jump (" + str(i) + ").png") for i in range(1, 9)]

        self.color = color
        self.rect = pygame.Rect(x,y,height,width)
        self.fps = 60
        self.next_frame_time = 0
        self.clock = pygame.time.Clock()
        self.direction = "jump"

        self.direction = "Idle"
        self.direction = "right"
        self.direction = "left"
        self.direction = "leftid"

        self.speed = 3
        self.anim_index = 0
        self.fall = 0
        self.isJump = False
        self.jumpCount = 10
    def get_rect(self):
        self.rect.topleft = (self.x,self.y)
        return self.rect
         

            
    def draw(self):
        self.rect.topleft = (self.x,self.y)
        if self.direction == "Idle":
            self.clock.tick(self.fps)
            image_list = self.idle

        elif self.direction == "right":
            self.clock.tick(self.fps)
            image_list = self.Right
                
        elif self.direction == "left":
            self.clock.tick(self.fps)
            image_list = self.left

        elif self.direction == "leftid":
            self.clock.tick(self.fps)
            image_list = self.leftid

        elif self.direction == "jump":
            self.clock.tick(60)
            image_list = self.jump

            
                # Is it time to show the next animation frame?
        time_now = pygame.time.get_ticks()
        if ( time_now > self.next_frame_time ):
                    # set the time for the next animation-frame
            inter_frame_delay = 1990 // self.fps   
            self.next_frame_time = time_now + inter_frame_delay  # in the future
                    # move the current image to the next (with wrap-around)
            self.anim_index += 1
            if self.anim_index >= len( image_list ):
                self.anim_index = 0
                            
        if self.anim_index >= len(image_list):
            self.anim_index = 0
        player_image = image_list[self.anim_index]

        player_image = image_list[self.anim_index]
        self.hitbox = (self.x, self.y + 30, 46,60)

        player_rect = player_image.get_rect(center = self.get_rect().center)
        player_rect.centerx += 0
        player_rect.centery += -20
        window.blit(player_image, player_rect)



我只是試圖回答。 也許您可以降低跌倒或跳躍的增量

    if not playerman.isJump: # -------------- make our player fall 
        playerman.y += playerman.fall
        playerman.fall += 0.1         #make the y increase slower, until you find the proper speed
        playerman.isJump = False

跳躍時間取決於跳躍算法中使用的常數 10。 使用jumpCountStart變量而不是此常量。

jumpCountStart = 50

跳躍的高度也取決於這個常數。 10 / jumpCountStart縮放跳躍,這樣跳躍的高度在跳躍減速時不會改變:

while run:
    # [...]

    if not playerman.isJump: 
        # [...]
        pass

    else:
        if playerman.JumpCount >= -jumpCountStart:
            jumpHeight = playerman.JumpCount * 10 / jumpCountStart
            playerman.y -= (jumpHeight * abs(jumpHeight)) * 0.4 * 10 / jumpCountStart
            playerman.JumpCount -= 1
        else:
            playerman.JumpCount = jumpCountStart
            playerman.isJump = False
   
            # [...]

不要忘記使用jumpCountStart JumpCount

class player:
    def __init__(self,x,y,height,width,color):
        # [...]

        self.JumpCount = jumpCountStart

Animation 與jumpCountStart = 50


您必須多次顯示相同的 animation 圖像。 例如,當jumpCountStart = 20時,您必須將每個圖像顯示 2 次。 jumpCountStart = 50時,您必須將每個圖像顯示 5 次。

self.jump = [pygame.image.load("grey_mouse/jump (" + str(i) + ").png")
             for i in range(1, 9)]
repeat = jumpCountStart // 10
self.jump = [self.jump[i // repeat] for i in range(len(self.jump) * repeat)]

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM