嘗試用 python map function Z945F3FC449518A73B9F5F32868DB46 內循環表達式解決

Question

n=10
fun=list(map(lambda x:[j for j in range(x)],n))
print(fun)

預計 output 是：

['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']

Answer 1

# using map (map works on an iterable)
n=10
fun=lambda x: (range(x)) # remember this is a function (so call it)
fun=list(map(str, fun(n)))
print(fun)

# directly
n=10
fun=list(map(str, (range(n))))
print(fun)

['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']
['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']

Python 文檔供參考：

• map() ： https://docs.python.org/3/library/functions.html#map
• range() ： https://docs.python.org/3/library/functions.html#func-range
• lambda() : https://docs.python.org/3/library/ast.html?highlight=3104BCAD8BZ04AEEBB2C