Trying to solve with python map function with lambda expression inside for loop

Question

n=10
fun=list(map(lambda x:[j for j in range(x)],n))
print(fun)

expected output is:

['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']

Answer 1

# using map (map works on an iterable)
n=10
fun=lambda x: (range(x)) # remember this is a function (so call it)
fun=list(map(str, fun(n)))
print(fun)

# directly
n=10
fun=list(map(str, (range(n))))
print(fun)

['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']
['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']

Python docs for reference:

• map() : https://docs.python.org/3/library/functions.html#map
• range() : https://docs.python.org/3/library/functions.html#func-range
• lambda() : https://docs.python.org/3/library/ast.html?highlight=lambda#ast.Lambda