Python：在元組列表中找到包含特定字符串的單詞

Question

我正在嘗試在 python 的列表列表中查找包含特定字符串的單詞，例如：如果我有一個元組列表，例如：

the_list = [
    ('Had denoting properly @T-jointure you occasion directly raillery'), 
    ('. In said to of poor full be post face snug. Introduced imprudence'),
    ('see say @T-unpleasing devonshire acceptance son.'),
    ('Exeter longer @T-wisdom gay nor design age.', 'Am weather to entered norland'),
    ('no in showing service. Nor repeated speaking', ' shy appetite.'),
    ('Excited it hastily an pasture @T-it observe.', 'Snug @T-hand how dare here too.')
    ]

我想找到我搜索的特定字符串並提取包含它的完整單詞，例如

for sentence in the_list:
    for word in sentence:
        if '@T-' in word:
            print(word)

   

Answer 1

import re

wordSearch = re.compile(r'word')
for x, y in the_list:
    if wordSearch.match(x):
        print(x)
    elif wordSearch.match(y):
        print(y)

Answer 2

您可以在您的扁平數組上使用理解列表：

from pandas.core.common import flatten

[[word for word in x.split(' ') if '@T-' in word] for x in list(flatten(the_list)) if '@T-' in x]
#[['@T-jointure'], ['@T-unpleasing'], ['@T-wisdom'], ['@T-it'], ['@T-hand']]

相關地方： 如何從列表列表中制作一個平面列表？ （特別是這個答案）， Double for 循環列表理解。

Answer 3

你需要使用 re 來完成這個任務

import re

a = re.search("@(.*?)[\s]",'Exeter longer @T-wisdom gay nor design age.')

a.group(0)

注意：您需要考慮 Nonetype 否則它將拋出錯誤

for name in the_list:
try:
    
    if isinstance(name,(list,tuple)):
        for name1 in name:
            result = re.search("@(.*?)[\s]",name1)
            print(result.group(0))
    else:
        
        result = re.search("@(.*?)[\s]",name)
        print(result.group(0))
    

except:
    pass