[英]Dynamically remove substring from string
我有一個有點直截了當的困境,但我一直無法找到解決方案。
我從 MongoDB 數據庫中獲取 JSON 文件並使用json.dumps將其轉換為字符串:
client = MongoClient("XXXX")
db = client.testdb
table = db.testingtable
document = table.find()
document = list(document)
docs = json.dumps(document,default=str)
print(docs)
當前 Output:
[{"_id": "67", "userId": 167, "productID": "Reference('product_id', ObjectId('5f4523b893d7b757bcbd2d71'))"}]
我將如何 go 關於動態搜索整個字符串以查找Reference
一詞,如果找到,它應該刪除括號內除字母數字值之外的所有內容,而不執行此操作:
docs.replace("Reference('product_id', ObjectId('",'').replace("'))",'')
預期 Output:
[{"_id": "67", "userId": 167, "productID": "5f4523b893d7b757bcbd2d71"}]
from pandas.io.json import json_normalize
df=pd.json_normalize([{"_id": "67", "userId": 167, "productID": "Reference('product_id', ObjectId('5f4523b893d7b757bcbd2d71'))"}])#convert to df
#Using regex, extract string between `ObjectId(`and `)` and turn it back to json
df.assign(productID=df.productID.str.extract('(?<=ObjectId\()(.*?)(?=\))')).to_json(orient="records")
[{"_id":"67","userId":167,"productID":"'5f4523b893d7b757bcbd2d71'"}]
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