[英]Dictionary Comprehension Value is List
嗨,我有以下字典。
players = {
"Brazil": [
(12, "Júlio César", "Goalkeeper", []),
(4, "David Luiz", "Defender", []),
(6, "Marcelo", "Defender", []),
(13, "Dante", "Defender", []),
(23, "Maicon", "Defender", []),
(5, "Fernandinho", "Midfielder", []),
(7, "Hulk", "Midfielder", []),
(8, "Paulinho", "Midfielder", []),
(11, "Oscar", "Midfielder", [90]),
(16, "Ramires", "Midfielder", []),
(17, "Luiz Gustavo", "Midfielder", []),
(19, "Willian", "Midfielder", []),
(9, "Fred", "Striker", []),
],
"Germany": [
(1, "Manuel Neuer", "Goalkeeper", []),
(4, "Benedikt Höwedes", "Defender", []),
(5, "Mats Hummels", "Defender", []),
(16, "Philipp Lahm", "Defender", []),
(17, "Per Mertesacker", "Defender", []),
(20, "Jérôme Boateng", "Defender", []),
(6, "Sami Khedira", "Midfielder", [29]),
(7, "Bastian Schweinsteiger", "Midfielder", []),
(8, "Mesut Özil", "Midfielder", []),
(13, "Thomas Müller", "Midfielder", [11]),
(14, "Julian Draxler", "Midfielder", []),
(18, "Toni Kroos", "Midfielder", [24, 26]),
(9, "André Schürrle", "Striker", [69, 79]),
(11, "Miroslav Klose", "Striker", [23]),
],
}
是否可以創建一個字典,其中包含所有巴西球員的名字作為鍵和第一個數字作為單行字典理解中的值? Output 應該是:
{'Júlio César': 12, 'David Luiz': 4, 'Marcelo': 6, 'Dante': 13, 'Maicon': 23, 'Fernandinho': 5, 'Hulk': 7, 'Paulinho': 8, 'Oscar': 11, 'Ramires': 16, 'Luiz Gustavo': 17, 'Willian': 19, 'Fred': 9}
當然有可能!
brazil = {player: number for (number, player, _, _) in players["Brazil"]}
# {'Júlio César': 12, 'David Luiz': 4, 'Marcelo': 6, 'Dante': 13, 'Maicon': 23, 'Fernandinho': 5, 'Hulk': 7, 'Paulinho': 8, 'Oscar': 11, 'Ramires': 16, 'Luiz Gustavo': 17, 'Willian': 19, 'Fred': 9}
這通過從源數據擴展元組列表中的每個元組來工作。 您要使用的鍵和值已命名,而下划線是表示您不想使用元組的這些部分的傳統方式
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