[英]Dictionary Comprehension Value is List
嗨,我有以下字典。
players = {
"Brazil": [
(12, "Júlio César", "Goalkeeper", []),
(4, "David Luiz", "Defender", []),
(6, "Marcelo", "Defender", []),
(13, "Dante", "Defender", []),
(23, "Maicon", "Defender", []),
(5, "Fernandinho", "Midfielder", []),
(7, "Hulk", "Midfielder", []),
(8, "Paulinho", "Midfielder", []),
(11, "Oscar", "Midfielder", [90]),
(16, "Ramires", "Midfielder", []),
(17, "Luiz Gustavo", "Midfielder", []),
(19, "Willian", "Midfielder", []),
(9, "Fred", "Striker", []),
],
"Germany": [
(1, "Manuel Neuer", "Goalkeeper", []),
(4, "Benedikt Höwedes", "Defender", []),
(5, "Mats Hummels", "Defender", []),
(16, "Philipp Lahm", "Defender", []),
(17, "Per Mertesacker", "Defender", []),
(20, "Jérôme Boateng", "Defender", []),
(6, "Sami Khedira", "Midfielder", [29]),
(7, "Bastian Schweinsteiger", "Midfielder", []),
(8, "Mesut Özil", "Midfielder", []),
(13, "Thomas Müller", "Midfielder", [11]),
(14, "Julian Draxler", "Midfielder", []),
(18, "Toni Kroos", "Midfielder", [24, 26]),
(9, "André Schürrle", "Striker", [69, 79]),
(11, "Miroslav Klose", "Striker", [23]),
],
}
是否可以创建一个字典,其中包含所有巴西球员的名字作为键和第一个数字作为单行字典理解中的值? Output 应该是:
{'Júlio César': 12, 'David Luiz': 4, 'Marcelo': 6, 'Dante': 13, 'Maicon': 23, 'Fernandinho': 5, 'Hulk': 7, 'Paulinho': 8, 'Oscar': 11, 'Ramires': 16, 'Luiz Gustavo': 17, 'Willian': 19, 'Fred': 9}
当然有可能!
brazil = {player: number for (number, player, _, _) in players["Brazil"]}
# {'Júlio César': 12, 'David Luiz': 4, 'Marcelo': 6, 'Dante': 13, 'Maicon': 23, 'Fernandinho': 5, 'Hulk': 7, 'Paulinho': 8, 'Oscar': 11, 'Ramires': 16, 'Luiz Gustavo': 17, 'Willian': 19, 'Fred': 9}
这通过从源数据扩展元组列表中的每个元组来工作。 您要使用的键和值已命名,而下划线是表示您不想使用元组的这些部分的传统方式
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.