Python 請求響應 - 如果 elif 條件不起作用

Question

嗨，我的代碼在 if else json 響應時遇到問題，我很確定我正在做正確的方法，但代碼不會在 else 語句中繼續。

import requests
import psycopg2
        conn = psycopg2.connect(dbname='databasename',user='postgres',password='12345',host='x.x.x.x', port='xxxx') # works correctly
        print('success db')
        cur = conn.cursor()

        cur.execute("SELECT mobile_number FROM users WHERE status='ACTIVE'") # this is my query 
        conn.commit();
        row_count = cur.rowcount
        print('This is the number of rows: ', row_count)
        result = [mobileNum[0] for mobileNum in cur.fetchall()]

        for mobileNum in result:
            print('Current Number: ', mobileNum)
            pushnotif = push_notif(mobileNum) # This is a function for http request
            
            if pushnotif['success'] == 1 and pushnotif['failure'] == 0 : # This line of code is working and continue the for loop
                print('Success!!!')
            elif pushnotif['success'] == 0 and pushnotif['failure'] == 1: # This line of code is working but only when I'm printing a sentence like faileedddd!
                print(pushnotif['results']['error']) # This doesn't print the result error on http response and exits the for loop
            elif pushnotif['message'] == "Invalid number": # This line doesn't work and end the for loops
                print(pushnotif['message'])
            else: # The code doesn't go here whenever the response is not 200 OK or push_notif['message'] or push_notif['results''error']
                print('error')

以下是響應示例：

{
    "multicast_id": xxx,
    "success": 1,
    "failure": 0,
    "canonical_ids": 0,
    "results": [
        {
            "message_id": "xxx"
        }
    ]
}

或者

{
    "multicast_id": xxxx,
    "success": 0,
    "failure": 1,
    "canonical_ids": 0,
    "results": [
        {
            "error": "invalid"
        }
    ]
}

或者

{
    "message": "Invalid number"
}

Answer 1

我不確定 function push_notif返回什么，但如果它返回常規dict ，這可能是一個問題，因為您假設字典中存在鍵(success, failure and result) ，但情況並非如此您提供的最后一個響應示例。 所以通常一個異常會引發並停止你的程序，或者至少如果被捕獲，會結束 for 循環並退出 function。

Answer 2

例如，假設您最初得到以下響應。

{
    "message": "Invalid number"
}

在這里，您的字典只有一個名為message的鍵。因此，當您使用諸如success 、 failure之類的鍵檢查響應時，您的程序將停止執行，因為這些鍵不存在於您當前的響應中，並且您的 else 語句將永遠不會執行。

Answer 3

pushnotif = push_notif(mobileNum)
pushlen = len(pushnotif)

if pushlen == 5:
     print("This will print if API response is equal to 5", pushnotif)
elif pushlen == 1:
     print("This will print if API response is equal to 1", pushnotif)
else:
     print("This will print unexpected response", pushnotif)

這是邏輯再次感謝您！