Pydroid 能識別 random.choice 嗎？

Question

這是我的代碼

user_action = input("enter rock, paper, or scissors:  ")
possible_action = ["rock", "paper", "scissors"]
computer_action = random.choice(possible_action)

它告訴我這是一個無效的變量。

我做錯了什么還是Pydroid的錯？

Answer 1

唯一可能的問題是您忘記了

隨機導入

這段代碼工作得很好：

import random
user_action = input("enter rock, paper, or scissors:  ")
possible_action = ["rock", "paper", "scissors"]
computer_action = random.choice(possible_action)
print(computer_action)