有誰知道如何使用 python 在solidworks 中進行革命？

Question

碰巧我有一個想要旋轉的草圖，我已經定義了旋轉，但我不知道如何 select 它應該旋轉的軸

 # make a new sketch on the Front Plane
        self.select_by_id2("Front Plane", "PLANE")
        self.insert_sketch()
        # sketch and dimension main tab shape
        self.create_line_vertical(self.height)
        self.create_line_horizontal(self.length, self.height)
        self.create_line_vertical1(self.length, self.height, self.height1)
        self.create_line_horizontal1(self.length, self.length1, self.height1)
        self.create_line_vertical2(self.length1, self.height1, self.height2)
        self.create_line_horizontal2(self.length1, self.length2, self.height2)
        self.create_line_vertical3(self.length2, self.height2)
        self.create_line_horizontal3(self.length2)
        self.select_by_id2("Line1", "SKETCHSEGMENT")
        self.add_dimension()
        # Revolve 360°
        self.select_by_id2("Sketch1", "SKETCH")
        self.select_by_id2("Line1", "AXIS")
        self.revolve_shaft()


def revolve_shaft(self):

        featureMgr.FeatureRevolve2(True, True, False, False, False, False,
                                   0, 0, 6.28318530718, 0, False, False,
                                   0.01, 0.01, 0, 0, 0, True, True, True)

Answer 1

根據FeatureRevolve2 Documentation ，您需要 select 帶有標記 0 的草圖和軸的標記 16。

在你的情況下，它應該是這樣的：

self.SelectByID2("Sketch1", "SKETCH", 0, 0, 0, False, 0, Nothing, swSelectOptionDefault)    
self.SelectByID2("Axis1", "AXIS", 0, 0, 0, True, 16, Nothing, swSelectOptionDefault)