如何檢查嵌套列表中的列或行是否具有相同的字符串

Question

我需要檢查嵌套列表是否有具有相同字符串的列

grid = [
  ["x", " ", "x"],
  ["x", " ", " "],
  ["x", "x", "x"]
]
#if grid has a column or row with the same string (such as the first column and last row) then it will say "yes"

我只設法為行做到這一點：

grid = [
  ["x", " ", "x"],
  ["x", " ", " "],
  ["x", " ", "x"]
]
print(grid)


row = ['x', 'x', 'x']


if row in grid:
  print("Yes")
else:
  print("no")

Answer 1

執行您需要的一種簡單方法是轉置主網格以檢查列，如下所示：

gridTranspose = list(zip(*grid))

這將基本上反轉網格中的行和列。

接下來，將您的列另存為一行（例如）

如果您的網格是：

[ 1 1 0 ]

只需以相同的方式創建變量（列 = [1, 1, 0]）

那么它應該工作！

Answer 2

-1表示不一樣

grid = [
  ["x", " ", "x"],
  ["x", " ", " "],
  ["x", "x", "x"]
]

row_same = [index if all(map(lambda x: x==i[0], i)) else -1 for index, i in enumerate(grid)] 
#[-1, -1, 2]
column_same = [j if all(map(lambda x: x==grid[0][j], [i[j] for i in grid])) else -1 for j in range(len(grid[0]))] 
#[0, -1, -1]

Answer 3

我有一個簡單易懂的解決方案。

因此，基本思想是獲取行列表並創建新的列列表，然后在它們之間進行檢查 -

num = range(len(grid)) # Just an extra var, so that it is readable

lst_of_columns = [[grid[j][i] for j in num] for i in num]
# This makes a list of columns. Take it slow, print it and understand the logic

for i in num: # These lines check if rows and columns are same
    for j in num:
        if grid[i] == lst_of_columns[j]: # grid[i] = row 1,2,3...
            print('yes')                 # lst_of_columns[j] = columns 1,2,3

        else:
            print('no')

我希望你明白這背后的邏輯。 此外，這適用於任意數量的行和列