用列表python中的數字替換哈希

Question

我有以下清單：

l = ['#Cars', 'Cars came into global', '##duo', '##go','#hello','##there']

我想替換為1.的第一個散列1.如果有兩個散列，我想為序列中的第一個雙散列獲得1.1和1.2. 對於第二個哈希。 下一個散列我想要2.依此類推這個邏輯。

結果應該是這樣的：

1. Cars
1.1 duo
1.2 go
2. hello 
2.2 there

Answer 1

嘗試這個：

a = ['#Cars', 'Cars came into global', '##duo', '##go','#hello','##there']

def hash(a):
    res = []
    major = 0
    minor = 0
    for s in a:
        if "#" in s:
            if "##" in s:
                minor += 1
                s = s.replace("##", "%d.%d " % (major, minor))
            else:
                major += 1
                minor = 0
                s = s.replace("#", "%d " % major)
        res.append(s)
    return res

hash(a)
['1 Cars', 'Cars came into global', '1.1 duo', '1.2 go', '2 hello', '2.1 there']

如果您不想保留沒有散列的項目，而只想打印，那么：

def hash(a):
    major = 0
    minor = 0
    for s in a:
        if "#" in s:
            if "##" in s:
                minor += 1
                s = s.replace("##", "%d.%d " % (major, minor))
            else:
                major += 1
                minor = 0
                s = s.replace("#", "%d " % major)
            print(s)

hash(a)
1 Cars
1.1 duo
1.2 go
2 hello
2.1 there

Answer 2

更短的遞歸解決方案：

from collections import defaultdict
l = ['#Cars', 'Cars came into global', '##duo', '##go','#hello','##there']
def to_hash(d, p = []):
   r, c, l = defaultdict(list), 0, None
   for a, *b in d:
      if a != '#' and p:
          yield f'{".".join(map(str, p))} {"".join([a, *b])}'
      elif a == '#':
          r[l:=((c:=c+1) if b[0] != '#' else c)].append(''.join(b))
   yield from [j for a, b in r.items() for j in to_hash(b, p+[a])]

print('\n'.join(to_hash(l)))

輸出：

1 Cars
1.1 duo
1.2 go
2 hello
2.1 there

Answer 3

您可以跟蹤頂級編號和子級別編號，也可以像這樣：-

lst = ['#Cars', 'Cars came into global', '##duo', '##go','#hello','##there']

top, nxt = 0, 0

for i in range(len(lst)):
    s = lst[i]
    if s[:2] == "##":
        nxt += 1
        lst[i] = s.replace("##", f"{top}.{nxt} ")
    elif "#" in s[:2]:
        top += 1
        nxt = 0
        lst[i] = s.replace("#", f"{top}. ")

for i in lst:
    print(i)

這里發生的事情是，循環獲取每個字符串並檢查字符串是否以"##"開頭，如果以"##"開頭，則增加子級別編號並用格式top.nxt替換"##" ，如果string 以單個散列"#"開頭，然后遞增頂部編號，將子級別編號設置為 0 並將"#"替換為頂部編號。