如何修改 matplotlib x 軸刻度標簽？

Question

這是一個示例代碼：

import matplotlib.pyplot as plt
import matplotlib.ticker as ticker
import numpy as np
import math
x = np.arange(0, math.pi*2, 0.05)
fig = plt.figure()
ax = fig.add_axes([0.1, 0.1, 0.8, 0.8])
y = np.sin(x)
ax.plot(x, y, marker='s')
ax.set_xlabel('angle')
ax.set_title('sine')
#ax.set_xticklabels([" ",1,2,3,4,5," "]) # don't work
ax.set_yticks([-1,0,1])
plt.show()

它創建了這個圖：

對於 x 軸，我想將 x 軸刻度標簽修改為僅顯示 1、2、3、4、5，而我想清除 0 和 6。我嘗試ax.set_xticklabels([" ",1,2,3,4,5," "])但這不起作用。 我得到了這個結果：

這個警告信息：

Warning (from warnings module):
  File "~/test.py", line 12
    ax.set_xticklabels(["",1,2,3,4,5,""]) # don't work
UserWarning: FixedFormatter should only be used together with FixedLocator

如何修改 x 軸刻度標簽以僅顯示 1、2、3、4、5？

Answer 1

您可以在調用ax.set_xticklabels ax.set_xticks之前使用 ax.set_xticks 設置 xticks。 請參見下面的代碼：

import matplotlib.pyplot as plt
import matplotlib.ticker as ticker
import numpy as np
import math
x = np.arange(0, math.pi*2, 0.05)
fig = plt.figure()
ax = fig.add_axes([0.1, 0.1, 0.8, 0.8])
y = np.sin(x)
ax.plot(x, y, marker='s')
ax.set_xlabel('angle')
ax.set_title('sine')
ax.set_xticks(np.arange(7))
ax.set_xticklabels([" ",1,2,3,4,5," "]) 
ax.set_yticks([-1,0,1])
plt.show()

output 給出：