將空格分隔的 txt 數組讀入 numpy

Question

我有一個充滿 .txt 文件的文件夾，格式如下（一個例子，下面的 0.txt）：

[[[ 2.1032608e+01  3.2608695e+00  1.4498953e-02]
  [ 2.1032608e+01  3.0978260e+00  6.5927312e-04]
  [ 3.0652174e+01  5.6739132e+01  1.1040760e-04]
  [ 3.0489130e+01  5.6576088e+01  6.9526240e-04]
  [ 1.6141304e+01  2.1684782e+01  1.5140385e-03]
  [ 1.6141304e+01  2.1684782e+01  2.4998910e-03]
  [ 3.5706520e+01  1.5163043e+01  1.5667630e-02]
  [ 3.5706520e+01  1.5163043e+01  5.1132514e-04]
  [ 1.6141304e+01  2.1521740e+01  9.0042617e-05]
  [ 1.5652174e+01  2.0217392e+01  4.7678968e-05]
  [ 3.3097828e+01  5.8043480e+01  2.3867608e-04]
  [ 1.5652174e+01  2.0217392e+01  1.3099676e-04]
  [ 1.7445652e+01  3.3097828e+01  8.3532266e-04]
  [ 1.8423914e+01  2.5597826e+01  1.5159410e-02]
  [ 3.8967392e+01  5.9673912e+01  6.5958439e-03]
  [ 3.8967392e+01  5.9673912e+01  9.2201140e-03]
  [ 1.5652174e+01  2.0054348e+01  9.5022479e-03]
  [ 3.3097828e+01  3.9782608e+01  1.6697637e-04]
  [ 3.3260868e+01  3.9619564e+01  2.7213297e-03]
  [ 3.3260868e+01  3.9619564e+01  2.1958089e-04]
  [ 1.6141304e+01  2.1684782e+01  5.6157220e-05]
  [ 2.1032608e+01  3.0978260e+00 -1.0377635e-05]
  [ 2.1032608e+01  3.0978260e+00 -8.7080858e-05]
  [ 1.5652174e+01  2.0217392e+01 -1.1274265e-04]
  [ 1.5652174e+01  2.0054348e+01 -5.1815634e-05]
  [ 3.2119564e+01  5.9673912e+01 -1.6645924e-04]
  [ 1.5652174e+01  2.0217392e+01  7.7641735e-06]
  [ 3.2608697e-01  1.7934783e+00  3.5882247e-05]
  [ 2.1032608e+01  3.0978260e+00  7.8685611e-05]
  [ 1.5652174e+01  2.0054348e+01  3.1178934e-05]
  [ 3.8967392e+01  5.9673912e+01  1.0482615e-04]
  [ 3.1956522e+01  5.6739132e+01  1.0767143e-03]
  [ 3.1793478e+01  5.6739132e+01  6.9617934e-04]
  [ 3.1956522e+01  5.6739132e+01  1.2175621e-04]
  [ 3.2119564e+01  5.9673912e+01  8.6526132e-05]
  [ 3.8967392e+01  5.9673912e+01  7.2365336e-05]
  [ 3.5706520e+01  1.5163043e+01  1.3151739e-04]
  [ 2.1032608e+01  3.0978260e+00  4.4964137e-05]
  [ 2.1032608e+01  3.0978260e+00 -1.4677797e-05]
  [ 3.5706520e+01  1.5163043e+01 -1.1417971e-05]
  [ 2.1032608e+01  3.0978260e+00  1.2694198e-05]
  [ 2.1032608e+01  3.0978260e+00  8.1792423e-05]
  [ 3.2119564e+01  5.9673912e+01 -4.8189460e-05]
  [ 1.5652174e+01  2.0217392e+01 -1.2792133e-04]
  [ 3.2445652e+01  5.9673912e+01 -1.1050291e-04]
  [ 1.5652174e+01  2.0217392e+01 -4.2534582e-05]
  [ 3.2282608e+01  5.9673912e+01 -3.9592214e-05]
  [ 3.2445652e+01  5.9673912e+01 -1.2300081e-04]
  [ 3.2119564e+01  5.9673912e+01  1.3895029e-04]
  [ 3.2119564e+01  5.9673912e+01  4.5048160e-04]
  [ 3.2119564e+01  5.9673912e+01  2.8149947e-03]
  [ 3.2119564e+01  5.9673912e+01  2.4660570e-03]
  [ 3.2119564e+01  5.9673912e+01  1.1084687e-05]
  [ 1.8423914e+01  2.5597826e+01  2.7254851e-05]
  [ 1.8423914e+01  2.5597826e+01  4.5520133e-06]
  [ 3.5706520e+01  1.5163043e+01  1.3295857e-05]
  [ 3.2282608e+01  5.9673912e+01  4.1052594e-06]
  [ 3.2119564e+01  5.9673912e+01  5.6243367e-05]
  [ 3.3097828e+01  5.8206520e+01  2.3062130e-05]
  [ 3.2119564e+01  5.9673912e+01  6.7559289e-05]
  [ 3.2119564e+01  5.9673912e+01  6.5806766e-05]
  [ 3.2119564e+01  5.9673912e+01  9.2756242e-04]
  [ 3.2119564e+01  5.9673912e+01  5.2335125e-04]
  [ 3.2282608e+01  5.9673912e+01  3.2513806e-05]
  [ 1.8423914e+01  2.5597826e+01  1.3968185e-05]
  [ 3.2119564e+01  5.9673912e+01  1.5303758e-05]
  [ 1.6141304e+01  2.1684782e+01  1.7933089e-05]
  [ 3.2119564e+01  5.9673912e+01  6.1444991e-04]
  [ 2.1032608e+01  3.0978260e+00  2.0746856e-04]
  [ 1.5652174e+01  2.0054348e+01 -9.7850330e-05]]]

有沒有辦法將其讀入二維 numpy 數組？ 請注意，它是由兩個空格分隔的空格，但是當存在負數時，- 符號將代替其中一個空格。 任何幫助將不勝感激！

我嘗試將它讀入 pandas 並以各種方式解析（使用 df.str 去除括號等），但我似乎無法讓它以科學記數法的方式工作。 我在這里嘗試了正則表達式方法。

Answer 1

利用：

import re
with open('01.txt') as file:
    p = file.read()

rows = p.split('\n')
ll = []
for row in rows:
    ll.append(re.findall('[\d+-\.e]+', row))
np.array(ll, dtype=float)

Output：

array([[ 2.1032608e+01,  3.2608695e+00,  1.4498953e-02],
   [ 2.1032608e+01,  3.0978260e+00,  6.5927312e-04],
   [ 3.0652174e+01,  5.6739132e+01,  1.1040760e-04],
   [ 3.0489130e+01,  5.6576088e+01,  6.9526240e-04],
   [ 1.6141304e+01,  2.1684782e+01,  1.5140385e-03],
   [ 1.6141304e+01,  2.1684782e+01,  2.4998910e-03],
   [ 3.5706520e+01,  1.5163043e+01,  1.5667630e-02],
   [ 3.5706520e+01,  1.5163043e+01,  5.1132514e-04],
   [ 1.6141304e+01,  2.1521740e+01,  9.0042617e-05],
   [ 1.5652174e+01,  2.0217392e+01,  4.7678968e-05],
   [ 3.3097828e+01,  5.8043480e+01,  2.3867608e-04],
   [ 1.5652174e+01,  2.0217392e+01,  1.3099676e-04],
   [ 1.7445652e+01,  3.3097828e+01,  8.3532266e-04],
   [ 1.8423914e+01,  2.5597826e+01,  1.5159410e-02],
   [ 3.8967392e+01,  5.9673912e+01,  6.5958439e-03],
   [ 3.8967392e+01,  5.9673912e+01,  9.2201140e-03],
   [ 1.5652174e+01,  2.0054348e+01,  9.5022479e-03],
   [ 3.3097828e+01,  3.9782608e+01,  1.6697637e-04],
   [ 3.3260868e+01,  3.9619564e+01,  2.7213297e-03],
   [ 3.3260868e+01,  3.9619564e+01,  2.1958089e-04],
   [ 1.6141304e+01,  2.1684782e+01,  5.6157220e-05],
   [ 2.1032608e+01,  3.0978260e+00, -1.0377635e-05],
   [ 2.1032608e+01,  3.0978260e+00, -8.7080858e-05],
   [ 1.5652174e+01,  2.0217392e+01, -1.1274265e-04],
   [ 1.5652174e+01,  2.0054348e+01, -5.1815634e-05],
   [ 3.2119564e+01,  5.9673912e+01, -1.6645924e-04],
   [ 1.5652174e+01,  2.0217392e+01,  7.7641735e-06],
   [ 3.2608697e-01,  1.7934783e+00,  3.5882247e-05],
   [ 2.1032608e+01,  3.0978260e+00,  7.8685611e-05],
   [ 1.5652174e+01,  2.0054348e+01,  3.1178934e-05],
   [ 3.8967392e+01,  5.9673912e+01,  1.0482615e-04],
   [ 3.1956522e+01,  5.6739132e+01,  1.0767143e-03],
   [ 3.1793478e+01,  5.6739132e+01,  6.9617934e-04],
   [ 3.1956522e+01,  5.6739132e+01,  1.2175621e-04],
   [ 3.2119564e+01,  5.9673912e+01,  8.6526132e-05],
   [ 3.8967392e+01,  5.9673912e+01,  7.2365336e-05],
   [ 3.5706520e+01,  1.5163043e+01,  1.3151739e-04],
   [ 2.1032608e+01,  3.0978260e+00,  4.4964137e-05],
   [ 2.1032608e+01,  3.0978260e+00, -1.4677797e-05],
   [ 3.5706520e+01,  1.5163043e+01, -1.1417971e-05],
   [ 2.1032608e+01,  3.0978260e+00,  1.2694198e-05],
   [ 2.1032608e+01,  3.0978260e+00,  8.1792423e-05],
   [ 3.2119564e+01,  5.9673912e+01, -4.8189460e-05],
   [ 1.5652174e+01,  2.0217392e+01, -1.2792133e-04],
   [ 3.2445652e+01,  5.9673912e+01, -1.1050291e-04],
   [ 1.5652174e+01,  2.0217392e+01, -4.2534582e-05],
   [ 3.2282608e+01,  5.9673912e+01, -3.9592214e-05],
   [ 3.2445652e+01,  5.9673912e+01, -1.2300081e-04],
   [ 3.2119564e+01,  5.9673912e+01,  1.3895029e-04],
   [ 3.2119564e+01,  5.9673912e+01,  4.5048160e-04],
   [ 3.2119564e+01,  5.9673912e+01,  2.8149947e-03],
   [ 3.2119564e+01,  5.9673912e+01,  2.4660570e-03],
   [ 3.2119564e+01,  5.9673912e+01,  1.1084687e-05],
   [ 1.8423914e+01,  2.5597826e+01,  2.7254851e-05],
   [ 1.8423914e+01,  2.5597826e+01,  4.5520133e-06],
   [ 3.5706520e+01,  1.5163043e+01,  1.3295857e-05],
   [ 3.2282608e+01,  5.9673912e+01,  4.1052594e-06],
   [ 3.2119564e+01,  5.9673912e+01,  5.6243367e-05],
   [ 3.3097828e+01,  5.8206520e+01,  2.3062130e-05],
   [ 3.2119564e+01,  5.9673912e+01,  6.7559289e-05],
   [ 3.2119564e+01,  5.9673912e+01,  6.5806766e-05],
   [ 3.2119564e+01,  5.9673912e+01,  9.2756242e-04],
   [ 3.2119564e+01,  5.9673912e+01,  5.2335125e-04],
   [ 3.2282608e+01,  5.9673912e+01,  3.2513806e-05],
   [ 1.8423914e+01,  2.5597826e+01,  1.3968185e-05],
   [ 3.2119564e+01,  5.9673912e+01,  1.5303758e-05],
   [ 1.6141304e+01,  2.1684782e+01,  1.7933089e-05],
   [ 3.2119564e+01,  5.9673912e+01,  6.1444991e-04],
   [ 2.1032608e+01,  3.0978260e+00,  2.0746856e-04],
   [ 1.5652174e+01,  2.0054348e+01, -9.7850330e-05]])

Answer 2

嗯，據我了解，你想要一個二維數組

所以階段是：

（偽-python）

data=get string from "0.txt" file.read()..etc

line_splitted=data.split('\n') # split by lines

2d_array=[]

for line in line_splitted:
# this is the method:      * space split   *the 'replace's are to remove the brackets
   2d_array.append(  line.split(' ').replace("[","").replace("]","") )

return 2d_array # you may convert it to numpy now, its a list of lists (2d list) , 
# /!\ each element is in string form, gotta be converted to float as well