如何正確統計list的總量

Question

我正在嘗試編寫一本會計賬簿，但在計算總金額時遇到了困難，可以在列表打印出來后進行計算，但數字不正確。 我試着用+來計算總量，但沒有用。

我究竟做錯了什么？

import os

def read_file(filename):
    items = []
    with open(filename, 'r', encoding='utf-8') as f:
        for line in f:
            if 'your product,your price' in line:
                continue
            #product,price = line.strip().split(',')
            #item.append([product, price])
        else:
            print("list>>> ----v")
        return item

def user_input(item):
    while True:
        product = input("\nitem:")
        if product == 'q':
            break
        price = input("\nprice:")
        price = int(price)
        item.append([product, price])
    return item

def print_file(item):
    for price in item:
        print(price[0], 'is: ', price[1])
        
        #total amount
        count = price[1]
        total_count = count + count
        num = (f"you spend total {total_count}")
    
        print(num)

def write_file(filename, item):
    with open(filename, 'w', encoding='utf-8') as f:
        f.write('your product,your price\n')
        for price in item:
            f.write(price[0] + ':' + str(price[1]) + '\n')

def main():
    filename = 'list.text'
    if os.path.isfile(filename):
        print("File Found")
        file = read_file(filename)

    else:
        print("Wlecome")
    item = []

    item = user_input(item)
    print_file(item)
    write_file('list.txt', item)

main()

Answer 1

您在添加計數時犯了一個小的命名錯誤，試試這個：

def print_file(item):
    total_count = 0
    for price in item:
        print(price[0], 'is: ', price[1])
        
        #total amount
        count = price[1]
        total_count += count
     num = (f"you spend total {total_count}")
    
     print(num)

Answer 2

選擇：

def print_file(item):
    total = 0
    for price in item:
        print(price[0], 'is: ', price[1])
        total += price[1]
    num = (f"you spend total {total_count}")

    print(num)

或者簡單地

def print_file(item):
    total = sum([price[1] for price in item])
    print(f"you spend total {total}")