[英]Python/Pandas:How to process a column of data when it meets certain criteria
[英]how to count data in a certain column in python(pandas)?
希望你做得很好 。 我嘗試在下表 [1] 中的另一個綠色行之后計算綠色行:df = pd.DataFrame([[green], [red], [red]], columns=['A'])
我試圖計算greengreen的代碼:
for index,row in data.iterrows():
if finalData['Color'].loc[i]=='green' & finalData['Color'].loc[i+1]=='green':
greengreen+=1
i+=1
但它沒有工作,希望你能幫忙。 注意:我是數據科學的新手
您可以使用:
# is the color green?
m = df['color'].eq('green')
# count the matches that precede another match
greengreen = (m&m.shift()).sum()
作為單線(python ≥ 3.8):
greengreen = ((m:=df['color'].eq('green'))&m.shift()).sum()
示例輸入:
df = pd.DataFrame({'color': ['green', 'green', 'green', 'red', 'green', 'red', 'green', 'green']})
輸出: 3
data = {'col1': ['A','B','C','D'],\
'col2': ['green','green', 'red','green']}
df = pd.DataFrame(data)
df
指數 | col1 | col2 |
---|---|---|
0 | 一個 | 綠色 |
1 | 乙 | 綠色 |
2 | C | 紅色的 |
3 | D | 綠色 |
df.col2.values
greengreen = 0
greenred = 0
redgreen = 0
for i in range(len(df.col2.values)):
if i < (len(df.col2.values)-1):
if df.col2.values[i] == 'green' and df.col2.values[i+1] == 'green':
greengreen += 1
elif df.col2.values[i] == 'green' and df.col2.values[i+1] == 'red':
greenred += 1
elif df.col2.values[i] == 'red' and df.col2.values[i+1] == 'green':
redgreen += 1
else:
print('?')
print(greengreen, greenred, redgreen)
1 1 1
國際大學聯合會,
count = (df['Color'].eq('green') & df['Color'].shift().eq('green')).sum()
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