簡體   English   中英

根據 r 中的邏輯向量保留數據幀的列

[英]keep columns of a dataframe according to logical vector in r

我有一個列中包含特征的數據框,並且每一列都有一個邏輯向量,無論它們是否滿足特定條件。 如果他們這樣做,則為 TRUE,如果他們不這樣做,則為 FALSE。

我只想保留滿足條件的列,並在邏輯向量中有一個TRUE

這是向量:

c(Adipocytes = TRUE, B.cells = TRUE, Basophils = FALSE, CD4..memory.T.cells = TRUE, 
CD4..naive.T.cells = TRUE, CD4..T.cells = FALSE, CD4..Tcm = TRUE, 
CD4..Tem = TRUE, CD8..naive.T.cells = FALSE, CD8..T.cells = TRUE, 
CD8..Tcm = TRUE, Class.switched.memory.B.cells = TRUE, DC = TRUE, 
Endothelial.cells = FALSE, Eosinophils = TRUE, Epithelial.cells = FALSE, 
Fibroblasts = TRUE, Hepatocytes = TRUE, ly.Endothelial.cells = TRUE, 
Macrophages = FALSE, Macrophages.M1 = TRUE, Macrophages.M2 = TRUE, 
Mast.cells = TRUE, Melanocytes = TRUE, Memory.B.cells = TRUE, 
Monocytes = FALSE, mv.Endothelial.cells = TRUE, naive.B.cells = TRUE, 
Neutrophils = TRUE, NK.cells = TRUE, pDC = TRUE, Pericytes = TRUE, 
Plasma.cells = TRUE, pro.B.cells = TRUE, Tgd.cells = TRUE, Th1.cells = FALSE, 
Th2.cells = TRUE, Tregs = FALSE)

和數據框:

structure(list(response = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 
1L), .Label = c("NoResponse", "Response"), class = "factor"), 
    Adipocytes = c(0.0147750026478847, 0.0147750026478847, 0.0147750026478847, 
    0.0212089093123119, 0.0710538305419062, 0.0147750026478847, 
    0.0147750026478847), B.cells = c(0.0771628600461939, 0.0348430059727367, 
    0.166843196901955, 0.029029065282152, 0.0289092657550142, 
    0.0091727181061411, 0.0545426703298063), Basophils = c(0.123412405513611, 
    0.229980789620818, 0.710327302827785, 0.110317426229336, 
    0.593651555059932, 0.171672288243263, 0.16957000805118), 
    CD4..memory.T.cells = c(0.053430101401256, 0.00519336879475164, 
    0.00519336879475164, 0.0135894934563294, 0.00519336879475164, 
    0.00519336879475164, 0.0187854542183181), CD4..naive.T.cells = c(0.0198799983437911, 
    0.0198799983437911, 0.0198799983437911, 0.0198799983437911, 
    0.0198799983437911, 0.0198799983437911, 0.0198799983437911
    ), CD4..T.cells = c(0.0308423390003806, -0.000280618433405845, 
    -0.000280618433405845, -0.000280618433405845, -0.000280618433405845, 
    -0.000280618433405845, 0.0119164432522563)), row.names = c("Pt1", 
"Pt10", "Pt103", "Pt106", "Pt11", "Pt17", "Pt2"), class = "data.frame")

您可以首先對您希望保留的列的名稱進行子集化,然后使用該名稱對原始數據框的列進行子集化。 在以下幾行中, cols 是您的向量,而 df 是數據框。

df[,names(cols[cols==T])]

嘗試這個

df[intersect(names(vec == T) , colnames(df))]

其中df是您的 data.frame 而vec是您的向量。

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM