[英]Trajectory optimization with gekko under speed constraints
PSA:我對壁虎很陌生,因此我可能在這里遺漏了一些非常明顯的東西。
我一直試圖找到最優控制問題的解決方案,即常規車輛的軌跡優化,在一定的速度限制下,在他們的行程中的特定距離。 為了做到這一點,我嘗試使用基於距離和速度約束數據的 pwl function 並使用v_max作為對 v 的約束。作為目標 function,我使用車輛比功率 (VSP) 近似值。
計算一直持續到最大值。 迭代次數達到並取消。 是否有一種方法可以離散化這個問題的搜索空間,使其在可接受的時間內解決,權衡計算時間以獲得准確性?
def optimal_trip(goal_dist, max_accel, max_decel, max_velocity, min_velocity, trip_time, distances ,speed_limits, slope):
model = GEKKO(remote=True)
model.time = [i for i in range(trip_time)]
x = model.Var(value=0.0)
v = model.Var(value=0.0, lb = min_velocity, ub = max_velocity)
v_max = model.Var()
slope_var = model.Var()
a = model.MV(value=0, lb=max_decel ,ub=max_accel)
a.STATUS = 1
#define vehicle movement
model.Equation(x.dt()==v)
model.Equation(v.dt()==a)
# path constraint
model.Equation(x >= 0)
#aggregated velocity constraint
model.pwl(x, v_max, distances, speed_limits)
model.Equation(v_max>=v)
#slope is modeled as a piecewise linear function
model.pwl(x, slope_var, distances, slope)
#End state constraints
model.fix(x, pos=trip_time-1,val=goal_dist) # vehicle must arrive at destination
model.fix(v, pos=trip_time-1,val=0) # vehicle must be fully stopped
#VSPI Objective function
obj = (v * (1.1 * a + 9.81 * slope_var + 0.132) +0.0003002*pow(v, 3))
model.Obj(obj)
# solve
model.options.IMODE = 6
model.options.REDUCE = 3
model.solve(disp=True)
return x.value, v.value, obj.value
有人可以對此有所了解嗎?
這是 model 的一個版本,其中包含成功求解的示例值:
from gekko import GEKKO
import numpy as np
min_velocity = 0
max_velocity = 10
max_decel = -1
max_accel = 1
distances = np.linspace(0,20,21)
goal_dist = 200
trip_time = 100
# set up PWL functions
distances = np.linspace(0,1000,10)
speed_limits = np.ones(10)*5
speed_limits[5:]=7
slope = np.zeros(10)
slope[3:5]=1; slope[7:9]=-1
model = GEKKO(remote=True)
model.time = [i for i in range(trip_time)]
x = model.Var(value=0.0)
v = model.Var(value=0.0, lb = min_velocity, ub = max_velocity)
v_max = model.Var()
slope_var = model.Var()
a = model.MV(value=0, lb=max_decel ,ub=max_accel)
a.STATUS = 1
#define vehicle movement
model.Equation(x.dt()==v)
model.Equation(v.dt()==a)
# path constraint
model.Equation(x >= 0)
#aggregated velocity constraint
model.pwl(x, v_max, distances, speed_limits)
model.Equation(v_max>=v)
#slope is modeled as a piecewise linear function
model.pwl(x, slope_var, distances, slope)
#End state constraints
model.fix(x, pos=trip_time-1,val=goal_dist) # vehicle must arrive at destination
model.fix(v, pos=trip_time-1,val=0) # vehicle must be fully stopped
#VSPI Objective function
obj = (v * (1.1 * a + 9.81 * slope_var + 0.132) +0.0003002*pow(v, 3))
model.Obj(obj)
# solve
model.options.IMODE = 6
model.options.REDUCE = 3
model.solve(disp=True)
您使用的值可能會導致不可行的解決方案。 以下是一些幫助 model 更可靠地解決問題的建議:
# remove these lines
#model.Equation(x >= 0)
#x = model.Var(value=0.0)
# put lower bound on x
x = model.Var(value=0,lb=0)
#End state constraints
# vehicle must arrive at destination
#model.fix(x, pos=trip_time-1,val=goal_dist)
# vehicle must be fully stopped
#model.fix(v, pos=trip_time-1,val=0)
p = np.zeros_like(model.time); p[-1]=1
final = model.Param(p)
model.Minimize(1e4*final*(v**2))
model.Minimize(1e4*final*((x-goal_dist)**2))
model.options.MAX_ITER=1000
model 的最終版本具有這些更改。 我可以幫助收斂到一個解決方案並避免最大迭代或不可行的解決方案。
from gekko import GEKKO
import numpy as np
min_velocity = 0
max_velocity = 10
max_decel = -1
max_accel = 1
distances = np.linspace(0,20,21)
goal_dist = 200
trip_time = 100
# set up PWL functions
distances = np.linspace(0,1000,10)
speed_limits = np.ones(10)*5
speed_limits[5:]=7
slope = np.zeros(10)
slope[3:5]=1; slope[7:9]=-1
model = GEKKO(remote=True)
model.time = [i for i in range(trip_time)]
x = model.Var(value=0.0, lb=0)
v = model.Var(value=0.0, lb = min_velocity, ub = max_velocity)
v_max = model.Var()
slope_var = model.Var()
a = model.MV(value=0, lb=max_decel ,ub=max_accel)
a.STATUS = 1
#define vehicle movement
model.Equation(x.dt()==v)
model.Equation(v.dt()==a)
#aggregated velocity constraint
model.pwl(x, v_max, distances, speed_limits)
model.Equation(v_max>=v)
#slope is modeled as a piecewise linear function
model.pwl(x, slope_var, distances, slope)
#End state constraints
# vehicle must arrive at destination
#model.fix(x, pos=trip_time-1,val=goal_dist)
# vehicle must be fully stopped
#model.fix(v, pos=trip_time-1,val=0)
p = np.zeros_like(model.time); p[-1]=1
final = model.Param(p)
model.Minimize(1e4*final*(v**2))
model.Minimize(1e4*final*((x-goal_dist)**2))
#VSPI Objective function
obj = (v * (1.1 * a + 9.81 * slope_var + 0.132) +0.0003002*pow(v, 3))
model.Minimize(obj)
# solve
model.options.IMODE = 6
model.options.REDUCE = 3
model.options.MAX_ITER=1000
model.solve(disp=True)
如果您在 StackOverflow 上提出另一個問題,請不要忘記包含一個最小且完整的工作示例來復制該問題。
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