我如何獲得這個 while 循環來更新我的初始輸入，以便我可以將 if 語句應用於 python 中的新值

Question

我想每次輸入一個新數字，將 integer 再次與當前變量進行比較，但也保存在原始變量之上，這樣我就可以輸入另一個數字再次進行比較。

我不確定為什么我不能用我輸入的變量更新當前變量。 我將如何實現這一目標。

我當前的代碼是：

print("give the first number: ", end = "")
g = input()
x = int(g)
finished = False
while not finished:
    print("enter the next number: ", end = "")
    k = input()
    h = int(k)
    if h == x and h != 0:
        print("same")
    elif h > x and h != 0:
        print("up")
    elif h < x and h != 0:
        print("Down")
    elif h != 0:
        h = x
    else:
        h == 0
        finished = True

如果程序正常工作，它將看起來像這樣：

Enter the first number: 9
Enter the next number (0 to finish): 9
Same
Enter the next number (0 to finish): 8
Down
Enter the next number (0 to finish): 5
Down
Enter the next number (0 to finish): 10
Up
Enter the next number (0 to finish): 10
Same
Enter the next number (0 to finish): 0

每個條目都應替換下一個條目將與之進行比較的變量。 任何幫助，將不勝感激。 謝謝！

Answer 1

您必須更新x變量，而不是h變量。 另外，我修復了代碼中的其他問題（見評論）

print("give the first number: ", end = "")
g = input()
x = int(g)
finished = False
while not finished:
    print("enter the next number: ", end = "")
    k = input()
    h = int(k)
    if h == 0:
        # Priority to the finish condition
        finished = True
    elif h == x:
        # No need to check that h != 0 because it's in the elsif
        print("same")
    elif h > x:
        print("up")
    elif h < x:
        print("Down")
        
    # Update the x variable, regardless of conditions. 
    x = h

這給出了您期望的 output。

give the first number: 9
enter the next number: 9
same
enter the next number: 8
Down
enter the next number: 5
Down
enter the next number: 10
up
enter the next number: 10
same
enter the next number: 0

Answer 2

您必須在 if 語句之外更新它。 所以而不是這個

elif h != 0:
        h = x

您可以像h = x一樣在循環之外執行此操作，但沒有 if 語句。