如何計算列表中任何和所有元素的總數百分比？

Question

from statistics import mean
names = []
votes = []

numCandidates = 5

for candidate in range(numCandidates):
    names.append(input("Enter Candidate {0}'s last name: ".format(candidate + 1))) 
    votes.append(int(input("Enter Candidate {0}'s amount of votes: ".format(candidate + 1)))) 

print()

print("Candidate\t Votes Received\t\t % of total votes")
for index,name in enumerate(names): 
    print(name,"\t\t",votes[index])
print()
print("Total Votes:\t",sum(votes))
print("Average votes:\t",mean(votes))
print()
print("Winner:\t\t",max(votes)) 
print("Lowest Votes:\t",min(votes)) 

我讓用戶創建兩個列表的輸入，一個用於名稱，一個用於投票數量。 然后我枚舉列表以給出表格的外觀：

Candidate        Votes Received          % of total votes
name1            5000
name2            3000
name3            4000
name4            7000
name5            6000

Total Votes:     25000
Average votes:   5000

Winner:          7000
Lowest Votes:    3000

現在，我希望占總數的百分比顯示占總數的百分比，例如對於name1應該是20.00% 。

我相信我需要像votes.index[1] / sum(votes)這樣的東西，但我不知道如何使索引“動態”。

我怎樣才能做到這一點？

Answer 1

感謝@fsimonjetz 提出正確答案。

我最終將其添加到 for 循環中：

round((votes[index]/sum(votes)*100),2),"%"

這樣把它變成：

for index,name in enumerate(names): # need to add titles to columns
    print(name,"\t\t",votes[index],"\t\t\t",round((votes[index]/sum(votes)*100),2),"%")